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AysviL [449]
3 years ago
12

Examples of constant speed

Physics
1 answer:
ki77a [65]3 years ago
6 0

Constant speed means the speed does not change at all for each second of the motion. Our <em>example</em> of driving a car on cruise control illustrates constant speed.

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Physical properties are those which can be measured or observed without changing the __________.
schepotkina [342]

Answer:

Physical properties are those which can be measured or observed without changing the substance.

Explanation:

Physical properties are properties that can be measured or observed without changing the chemical nature of the substance. Some examples of physical properties are: color (intensive) density (intensive)

<u><em>Answer is B. Substance</em></u>

<u><em>Hope that helps</em></u>

7 0
4 years ago
What is the total resistance of circuit when resistors connected in series and parallel?
Lostsunrise [7]

Explanation:

In series combination

R = R1 + R2 + R3 + ...+ Rn

In parallel combination

1/R = 1/R1 + 1/R2 + 1/R3 + ...+ 1/Rn

4 0
3 years ago
When gravity overcomes the nuclear energy in a red supergiant, the star begins to collapse, leading to a massive explosion that
zlopas [31]

The answer for this would be a supernova. This is a momentary astronomical happening that transpires during the last stellar evolutionary phases of a huge star's life, whose annihilation is noticeable by one concluding titanic explosion that takes place in space.

6 0
3 years ago
A uniform electric field exists in the region between two oppositely charged plane parallel plates. A proton is released from re
spayn [35]

The magnitude of the electric field can be calculated using the equation

E = \frac{F}{q}, where F is the Force acting on the proton and q is the charge of the proton.

We know that the charge of the proton is q = 1.6 x 10^{-19}  C

We have to calculate the Force first.

We know that F = ma from Newton's 2nd law, where m is the mass of the proton and a is the acceleration.

We know that the mass of the proton m = (1.67) X 10^{-27}  kg

So it turns out that we have to calculate acceleration before anything else.

In order to calculate the acceleration, we make use of the following data from the question:

Initial Velocity of the proton V_{i}  = 0

Distance traveled  D = 1.70 cm = 0.017 m

Time taken for the travel between the plates t = (1.48) X 10^{-6}  s

Acceleration a = ?

Using the equation, D = V_{i}t + \frac{1}{2} at^{2}, we get

Knowing that initial velocity is 0, the equation reduces to D = \frac{1}{2}at^{2}

Rearranging the equation so as to make a the subject of the formula, we have

a = \frac{2D}{t^{2} }

Plugging in the numbers and simplifying gives us a = 1.5 x 10^{10}   m/s^{2}

We can now calculate the Force using F = ma

Plugging in the known values, we get F = 2.5 x 10^{-17}  N

Using this, we can calculate E through the equation E = \frac{F}{q}

Plugging the numbers and simplifying gets us E = 156.25 N/C

Thus, the magnitude of the electric field between the plates of the capacitor is 156.25 N/C


B) To calculate the Final Velocity of the proton, we can make use of the equation

V_{f}  = V_{i}  + at

Plugging the numbers in and simplifying gets us V_{f}  = (2.22)  *  10^{4}  m/s

5 0
4 years ago
Read 2 more answers
if it takes 4J work to stretch a hooke's law spring 10 cm from its equilibrium length, determine the extra work required to stre
AnnZ [28]

Answer:

12 J

Explanation:

The amount of energy stored in a spring stretched by a distance x is:

E = 1/2 k x², where k is the stiffness of the spring.

So the spring has 4J of energy when it is stretched 10 cm:

4 J = 1/2 k (0.10 m)²

k = 800 N/m

When the stretched to 20 cm, the amount of energy is:

E = 1/2 (800 N/m) (0.20 m)²

E = 16 J

So it takes an additional 12 J to stretch the spring an additional 10 cm.

5 0
3 years ago
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