Answer:
Option B is the correct answer.
Explanation:
Refer the figure we have centripetal force at bottom of circle
We have mass, m = 2 kg
Radius, r = 1.2 m
For circular motion to occur we have tension at top = 0
That is
Now let us find tension at bottom point
Option B is the correct answer.
Answer: 0.81 GHz
Explanation:As written in the question police radars works by determining the beat frequency between sent and reflected wave. This beat frequency is just difference of the frequencies of the sent and reflected wave.
To Calibrate the Radar the turning fork must produce the beat frequency similar to that produce by reflected wave at right speed which in this case is 55mph
Hence we know that turning fork frequency=Δf
Δf=f'-f
here f=10.5 Ghz
f=10.5 *10^9
f=10500000000
also
v_s=55mph
v_s=24.5872 m/s
since the source is moving a/c to doppler effect
taking speed of sound to be v=344m/s
f'=11.3*10^9
Δf=8.08*10^8
Δf=0.81 GHz
If you have no way to accurately measure all of the object's bumps and dimples, then the only way to measure its volume is by means of fluid displacement.
-- Put some water into a graduated (marked) container, read the amount of water, drop the object into the container, and read the new volume in the container. The volume of the object is the difference between the two readings.
-- Alternatively, stand an unmarked container in a large pan, and fill it to the brim. Slowly slowly lower the object into the unmarked container, while the pan catches the water that overflows from it. When the object is completely down in the container, carefully remove the container from the pan, and measure the volume of the water in the pan. It's equal to the volume of the object.
The answer is b that what I think and feel like it is
Answer:
1 μF
Explanation:
To obtain the answer to the question, all we need to do is to calculate the equivalent capacitance of the capacitors. This can be obtained as illustrated below.
From the question given above, the following data were obtained:
Capacitor 1 (C₁) = 2 μF
Capacitor 2 (C₂) = 4 μF
Capacitor 3 (C₃) = 4 μF
Equivalent capacitance (Cₑq) =?
Cₑq = 1/C₁ + 1/C₂ + 1/C₃
Cₑq = 1/2 + 1/4 + 1/4
Cₑq = (2 + 1 + 1)/4
Cₑq = 4/4
Cₑq = 1 μF
Thus, the answer to the question is 1 μF
