Question

On a cloudless day, the sunlight that reaches the surface of the earth has an intensity of about W/m². What is the electromagnetic energy contained in 5.20 m³ of space just above the earth's surface?

Answer 1

Answer:

1.907 x 10⁻⁵ J.

Explanation:

Given,

Volume of space, V = 5.20 m³

Assuming the intensity of sunlight(S) be equal to 1.1 x 10³ W/m².

Electromagnetic energy = ?

$E = \mu V$

$E = (\dfrac{S}{c})\times V$

where c is the speed of light.

$E = (\dfrac{1.1\times 10^3}{3\times 10^8})\times 5.20$

$E = 1.907\times 10^{-5}\ J$

Hence, Electromagnetic energy is equal to 1.907 x 10⁻⁵ J.