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ArbitrLikvidat [17]
3 years ago
9

On a cloudless day, the sunlight that reaches the surface of the earth has an intensity of about W/m². What is the electromagnet

ic energy contained in 5.20 m³ of space just above the earth's surface?
Physics
1 answer:
Otrada [13]3 years ago
4 0

Answer:

1.907 x 10⁻⁵ J.

Explanation:

Given,

Volume of space, V = 5.20 m³

Assuming the intensity of sunlight(S) be equal to 1.1 x 10³ W/m².

Electromagnetic energy = ?

E = \mu V

E = (\dfrac{S}{c})\times V

where c is the speed of light.

E = (\dfrac{1.1\times 10^3}{3\times 10^8})\times 5.20

E = 1.907\times 10^{-5}\ J

Hence, Electromagnetic energy is equal to 1.907 x 10⁻⁵ J.

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Speed of car A is given as

v_a = 70 mph

now we need to convert it into SI units

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1 hour = 3600 s

now we have

v_a = 70 *\frac{1609}{3600} = 31.3 m/s

now its distance from Bambi is given as

d_a = 350 m

time taken by it to hit the Bambi

t = \frac{d}{v}

t = \frac{350}{31.3}

t = 11.2 s

Now other car is moving at speed 50 mph

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v_b = 50* \frac{1609}{3600}

v_b = 22.35 m/s

now its distance from Bambi is given as

d_b = 590 feet

as we know that 1 feet = 0.3048 m

d_b = 590*0.3048 = 179.83 m

now the time to hit the other car is

t_2 = \frac{179.83}{22.35}

t_b = 8.05 s

So Car B will hit the Bambi first

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Answer:

laser pointer does not make use of total internal reflection

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2 years ago
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Answer:

I HOPE THIS IS CORRECT

Explanation:

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difference in temperature ΔT=70−10=60oC

Concept

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   2000×t=200×4200×60

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or   t=25.2×103sec.

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