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Sladkaya [172]
3 years ago
8

a closed system consitts of a pendumluem that is swinging back and forth. if the pendulums gravitational potential energy decrea

ses, what else must happen to the energy of the system.
Physics
1 answer:
maw [93]3 years ago
7 0

Answer:

Its gravitational potential energy must increase.

Explanation:

<u>Conservation of Mechanical Energy</u>

The total amount of mechanical energy, in a closed system in the absence of dissipative forces like friction or air resistance, remains constant.

This means that energy cannot disappear or appear and that potential energy can become kinetic energy or vice versa.

In a closed system like a pendulum, two types of energies are considered: Gravitational potential (U) and kinetic (K). Thus, the sum of both energies must remain constant in time.

Suppose the pendulum is at a state where U=150 J, and K=350 J. The total mechanical energy is:

M = 150 J + 350 J = 500 J

If the kinetic energy decreases to a new value, say K = 200 J, then the gravitational potential must increase to compensate for this new condition, that is: U = 300 J

So, It's gravitational potencial energy must increase

Hope it helps you I'm from ph :)

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gives the speed v versus time t for a 0.500 kg object of radius 6.00 cm that rolls smoothly down a 30° ramp. The scale on the ve
ddd [48]

Answer:

Rotational inertia of the object is given as

I = 7.2 \times 10^{-4} kg m^2

Explanation:

As we know that the acceleration of the object on inclined plane is given as

a = \frac{gsin\theta}{1 + k^2/R^2}

now we know that velocity at any instant of time is given as

v = at

now we know that if the graph between velocity and time is given then the slope of the graph will be same as acceleration

so here we have

\frac{gsin\theta}{1 + k^2/R^2} = slope

now from the graph slope of the graph is given as

slope = \frac{3.5 - 0}{1}

\frac{gsin\theta}{1 + k^2/R^2} = 3.5

\frac{9.81 sin30}{1 + k^2/R^2} = 3.5

k^2 = 0.4 R^2

now rotational inertia is given as

I = mk^2

I = 0.5(0.4)(0.06)^2

I = 7.2 \times 10^{-4} kg m^2

8 0
4 years ago
A 70 kg human sprinter can accelerate from rest to 10 m/s in 3.0 s. During the same time interval, a 30 kg greyhound can go from
ladessa [460]

Answer:

P_1 = 1166.7 Watt

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Explanation:

Average power for the human sprinter is given as

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so we have

P = \frac{\frac{1}{2}mv^2 - 0}{\Delta t}

P = \frac{\frac{1}{2}(70)(10^2) - 0}{3}

P_1 = 1166.7 Watt

Average power for greyhound is given as

P = \frac{\frac{1}{2}mv^2 - 0}{\Delta t}

P = \frac{\frac{1}{2}(30)(20^2) - 0}{3}

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3 0
3 years ago
A school bus takes 0.530 h to reach the school from your house. If the average velocity of the bus is 19.0 km/h to the east, wha
kifflom [539]

Answer:

x_{distance}=10.07km

Explanation:

Given data

time=0.530 h

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To find

Displacement Δx

Solution

The Formula for average velocity is given as

V_{avg}=(x_{distance} )/(t_{time} )\\ x_{distance}=V_{avg}*(t_{time} )\\x_{distance}=(19.0km/h)*(0.530h)\\x_{distance}=10.07km

3 0
4 years ago
What is the change in potential energy of a squirrel that jumps from a tree branch that is 4.5 meters off of the ground and land
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Answer:

16.3 joules...................

3 0
3 years ago
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andre [41]

Answer:

d is your answer

Explanation:

4 0
3 years ago
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