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mojhsa [17]
3 years ago
9

The value of a car decreases by 20 percent per year. Mr. Sing purchases a $22,000 automobile. What is the value of the car at th

e end of the second year?
A$14,080
B$17,600
C$19,800
D$26,400
Mathematics
2 answers:
iris [78.8K]3 years ago
8 0
The answer is A: 14,080
andriy [413]3 years ago
6 0

Answer:

not too sure but I think its C or D

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A dice is rolled 4 times. What is the probability of showing a 6 on every roll?
marin [14]

Answer:

4/24 times

Step-by-step explanation:

Since there are 6 sides on a dice and it's rolled 4 times you would need to do 6*4 which is 24, then every number could have the probability of 4/24 to get rolled every time.

5 0
3 years ago
What is 12x^2 + 16x^3
yarga [219]

Answer:

4x^2(3+4x)

Step-by-step explanation:

3 0
3 years ago
Find the slope given the following information <br> (3,7) and (-4,10)
hram777 [196]

Answer:

m=-3/7

Step-by-step explanation:

m=rise/run=Δy/Δx

m=y2−y1/x2−x1

m=10−7/−4−3

m=3/−7

m=−3/7

6 0
2 years ago
A large fish tank at an aquarium needs to be emptied so that it can be cleaned. When its
VikaD [51]

Answer:

The draining time when only the big drain is opened is 2.303 hours.

The draining time when only the small drain is opened is 5.303 hours.

Step-by-step explanation:

From Physics, we know that volume flow rate (\dot V), measured in liters per hour, is directly proportional to draining time (t), measured in hours. That is:

\dot V \propto \frac{1}{t}

\dot V = \frac{k}{t} (Eq. 1)

Where k is the proportionality constant, measured in liters.

From statement, we have the following three expressions:

(i) <em>Large and small drains are opened</em>

\dot V_{s}+\dot V_{l} = \frac{k}{2} (Eq. 2)

\frac{\dot V_{s}+\dot V_{l}}{k} = \frac{1}{2}

(ii) <em>Only the small drain is opened</em>

\dot V_{s} = \frac{k}{t_{l}+3} (Eq. 3)

\frac{\dot V_{s}}{k} = \frac{1}{t_{l}+3}

(iii) <em>Only the big drain is opened</em>

\dot V_{l} = \frac{k}{t_{l}} (Eq. 4)

\frac{\dot V_{l}}{k}  = \frac{1}{t_{l}}

By applying (Eqs. 3, 4) in (Eq. 2) and making some algebraic handling, we find that:

\frac{1}{t_{l}+3}+\frac{1}{t_{l}} = \frac{1}{2}

\frac{t_{l}+t_{l}+3}{t_{l}\cdot (t_{l}+3)} = \frac{1}{2}

2\cdot t_{l}+3 = t_{l}^{2}+3\cdot t_{l}

t_{l}^{2}-t_{l}-3 = 0 (Eq. 5)

Whose roots are determined by the Quadratic Formula:

t_{l,1}\approx 2.303\,h and t_{l,2} \approx -1.302\,h

Only the first roots offers a solution that is physically reasonable. Hence, the draining time when only the big drain is opened is 2.303 hours. And the time needed for the small drain is calculated by the following formula:

t_{s} = 2.303\,h+3\,h

t_{s} = 5.303\,h

The draining time when only the small drain is opened is 5.303 hours.

7 0
3 years ago
A triangle with a 135° angle​
GuDViN [60]

Answer:

The 135 external angle means its corresponding internal angle is (180–135) 45 degrees. The other internal angle of 65 plus the 45 is 110 degrees. Since the sum of degrees in the angles in a triangle is 180, the other interior angle is (180–110), or 70 degrees.

Step-by-step explanation:

6 0
3 years ago
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