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Ilya [14]
3 years ago
12

250 mL of water is collected during a combustion reaction. The temperature in the

Chemistry
1 answer:
klio [65]3 years ago
7 0

Answer:

10.67 moles is the answers.hope it helped

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Please help me ill give brainiest to the right answer
valina [46]

Answer:

its c or a

Explanation:

7 0
3 years ago
Read 2 more answers
How many moles of aluminum do 4.60x10^24 aluminum represent? Express your answer using three significant figures.
stiks02 [169]

Answer:

              7.64 Moles

Explanation:

                      As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.

The relation between Moles, Number of Particles and Avogadro's Number is given as,

                          Number of Moles  =  Number of Particles ÷ 6.022 × 10²³

Putting values,

                          Number of Moles  =  4.60 × 10²⁴ Particles ÷ 6.022 × 10²³

                         Number of Moles  =  7.64 Moles

6 0
3 years ago
Calculate the volume of 12.0 g of helium at 100°c and 1.2 atm
hodyreva [135]

Volume = nRT/P

n = number of particles (moles)

R = universal gas constant (0.0821)

T = temperature (Kelvin)

P = pressure (atm)

(Assuming you have 1 mole of Helium in a chemical reaction) We would need to convert grams to moles: 12.0g He x 1 mol He/4 molar mass of He = 3 mol He

Convert Celsius to Kelvin: 100*C + 273.15 = 373.15 K

Now we can set up the equation for volume: (3mol)(0.0821)(373.15)/1.2atm = 76.6 L of Helium gas

8 0
3 years ago
Which equation shows how wavelength is related to velocity and frequency?
Nataly_w [17]

Answer:

The correct option is the option;

\lambda = \dfrac{v}{f}

Explanation:

The wavelength of a wave is the distance between two successive crests of the wave

Therefore, the wavelength, λ, is given by the fraction of the velocity, <em>v</em>, of the wave divided by the frequency, <em>f</em>, (the number of cycles that pass through a point) of the wave

Mathematically, we have;

The \ wavelength, \ \lambda = \dfrac{The \ wave \ velocity, \ v}{The \ wave \ frequency, \ f}

\lambda = \dfrac{v}{f}

4 0
3 years ago
What is the percent error for the experiment if the actual density is
OLga [1]

Answer:

<h3>The answer is 40.96%</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual density = 2.49g/mL

error = 2.49 - 1.47 = 1.02

We have

p(\%) =  \frac{1.02}{2.49}  \times 100 \\ = 40.96385542...

We have the final answer as

<h3>40.96 %</h3>

Hope this helps you

4 0
3 years ago
Read 2 more answers
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