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LiRa [457]
3 years ago
15

In which stage of the cell cycle does the division of the nucleus occur?

Chemistry
1 answer:
trasher [3.6K]3 years ago
6 0
The division of the nucleus occurs durning the M phase
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Duncan takes a break from studying and goes to the gym to swim laps If swimming burns amount of time ? 85 * 10 ^ 5 cal per hour
Volgvan

When 6.85×10⁵ cal is converted to kilojoules, the result obtained is 2866.04 KJ

<h3>Data obtained from the question </h3>
  • Energy (cal) = 6.85×10⁵ cal
  • Energy (KJ) =?

<h3>Conversion scale </h3>

1 cal = 0.004184 KJ

<h3>How to convert 6.85×10⁵ cal to kilojoules</h3>

1 cal = 0.004184 KJ

Therefore,

6.85×10⁵ cal = 6.85×10⁵ × 0.004184

6.85×10⁵ cal = 2866.04 KJ

Thus, 6.85×10⁵ cal is equivalent to 2866.04 KJ

Learn more about conversion:

brainly.com/question/2139943

6 0
2 years ago
Help me please, will give brainliest if correct!
mafiozo [28]
The answer would be C
4 0
3 years ago
Read 2 more answers
Test your knowledge of water's ability to dissolve
VladimirAG [237]

Answer: 1 dissociation. 2. Hydration. 3. Dissolving.

Explanation:

5 0
3 years ago
A solution has a Ph of 3.73. The pOH of this solution is?
ollegr [7]
PH + pOH = 14.
So, subtract 3.73 from 14.

The pOH is 10.27 :)
7 0
3 years ago
A 25.0 mL sample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 37.5
Soloha48 [4]
This is all i know
First of all, let's write the equation of the reaction.
CH₃COOH + NaOH ⇒ CH₃COONa + H₂O
The formula to be used here is CaVa/CbVb = na/nb
where Ca is the concentration of the acid (?)
Cb is the concentration of the base (0.175M)
Va is the volume of the acid (25 mL)
Vb is the volume of the base (37.5 mL)
na is the number of moles of acid (1)
nb is the number of moles of base (1)
Ca × 25/0.175 × 37.5 = 1/1
Ca = 0.175 × 37.5 × 1 /25 ×1
Ca = 0.263 M
The concentration of the acid in the sample was 0.263 M

5 0
3 years ago
Read 2 more answers
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