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max2010maxim [7]
2 years ago
12

X(x+1)+(x+1)(x+2)+(x+2)(x+3) solve the equation for x​

Mathematics
2 answers:
muminat2 years ago
6 0

Answer:

3 x^{2} + 9x + 8

<em><u>(This is an expression, not an equation so you can't find x with this expression. Equations have an = sign which can help isolate x on one side to find the value of x. This is the closest thing you could do for an answer for this expression.)</u></em>

Step-by-step explanation:

x(x+1)+(x+1)(x+2)+(x+2)(x+3)

= (x)(x) + (x)(1) + (x)(x) + (x)(2) + (1)(x) + (1)(2) + (x)(x) + (x)(3) + (2)(x) + (2)(3)

= <em>x^2</em> + x + <em>x^2</em> + 2x + x+ <u>2</u> + <em>x^2</em> + 3x + 2x + <u>6</u>

= (<em>x^2+x^2+x^2</em>) + (x+2x+x+3x+2x) + (<u>2+6</u>)

= 3x^{2} + 9x + 8

So first you expand the brackets and then you combine like terms.

viva [34]2 years ago
4 0

Answer:

3x²+9x+8

Step-by-step explanation:

x²+x+x(x+2)+1(x+2)+x(x+3)+2(x+3)

x²+x+x²+2x+x+2+x²+3x+2x+6

x²+x²+x²+x+2x+x+3x+2x+2+6

3x²+9x+8

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Consider firing a pumpkin from a canon at a target that is 17 meters away. The pumpkin follows a quadratic path as displayed to
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A.
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(2.6,7.9)
(4.8,12.4)
(9.7,15.1)

b.
well, the points don't look like they are on the line but they actually are (plot twist)


so
since (0,0) is on th egarph

0=a(0)²+b(0)+c
0=c
so
f(x)=ax²+bx+0 or
f(x)=ax²+bx

find a and b
sub points

(2.6,7.9)
7.9=a(2.6)²+b(2.6)
7.9=6.76a+2.6b

(4.8,12.4)
12.4=a(4.8)²+b(4.8)
12.4=23.04a+4.8b

use those 2 equations
7.9=6.76a+2.6b
12.4=23.04a+4.8b

eliminate b
multiply first equation by -4.8 and 2nd by 2.6 and add them
-37.92=-32.448a-12.48b
32.24=59.904a-12.48b +
-5.68=27.456a+0b

-5.68=27.456a
divide both sides by 27.456
(-5.68/27.456)=a
find b

12.4=23.04a+4.8b
12.4=(-130.8672/27.456)+4.8b
12.4+(130.8672/27.456)=4.8b
(12.4+(130.8672/27.456))/4.8=b

da equation is
y= \frac{-5.68}{27.456} x^2+ \frac{12.4+\frac{130.8672}{27.456}}{4.8}x



c. the roots are found with your calculator
the roots are at x=0 and x=17.287323943662
so very close to the target but not exactly on it
if the target has a radius of 0.287323943662 or more then it will hit the target
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