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3 years ago

the accompanying graph shows the elevation of a certain region in new york state as a hiker travels along a trail.

Mathematics

1 answer:

FrozenT [24]3 years ago

7 0

Answer:

0<x<12

Step-by-step explanation:

These signs < should have a line under it btw

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Aleksandr [31]

Answer:

741.415866247

Step-by-step explanation:

8 0

3 years ago

Which is the length of HJ expressed in terms of pi?

Pani-rosa [81]

Answer:

B. 9/20 $\pi$

Step-by-step explanation:

the circumference is 2 $\pi$ r. Since the radius is one, that would be 2 $\pi$ .

81/360=0.225, or 22.5% of the circumference. 22.5% of 2 $\pi$ is 0.45 $\pi$ . 0.45=9/20, so the answer is B.

CHECK: 2 $\pi$ = 6.283

6.283x0.225=0.14137, or 9/20 $\pi$

4 0

3 years ago

Calculate the rate of change. 0 1 2 3 4 5 15 25 40 60 85 115

Arte-miy333 [17]

Dy/dx=10,15,20,25,30

d2y/dx2=5,5,5,5,5 (there is no "rate of change" that is constant because acceleration is positive meaning that velocity keeps increasing...)

Since d2y/dx2 is constant, acceleration is constant, and this means that it is a quadratic equation of the form y=ax^2+bx+c

There are only three unknowns so we can use just three data points.

9a+3b+c=60
4a+2b+c=40
a+b+c=25 getting differences between these...

5a+b=20
3a+b=15 and again...

2a=5, so a=2.5, making 3a+b=15 become:

7.5+b=15, so b=7.5, making a+b+c=25 become:

2.5+7.5+c=25, so c=15

So the quadratic which produced the table is:

y=2.5x^2+7.5b+15

This is the regular old position function you see with any object moving with constant acceleration (like gravity when simplified).

The acceleration is 2.5 it has an initial velocity of 7.5 and an initial position of 15.

8 0

3 years ago

Please solve this math for me it’s urgent don’t write unnecessary stuffs or spam or else I’ll report

loris [4]

Answer:

Step-by-step explanation:

Find k such that

f [x] = x4 - kx2 + kx + 2

4 0

3 years ago

Given u( – 5) = -5, u'( – 5) = 2, U( – 5) = 6, v'( – 5) = 4, find w'( – 5).

Aleonysh [2.5K]

(a) w(x) = 5u(x) + 8v(x)

Differentiating with the sum rule gives

w'(x) = 5u'(x) + 8v'(x)

so that

w' (-5) = 5u' (-5) + 8v' (-5)

… = 5×2 + 8×4 = 42

(b) w(x) = u(x) v(x)

Differentiate using the product rule:

w'(x) = u'(x) v(x) + u(x) v'(x)

Then

w' (-5) = u' (-5) v (-5) + u (-5) v' (-5)

… = 2×6 + (-5)×4 = -8

(c) w(x) = u(x) / v(x)

Quotient rule:

w'(x) = (u'(x) v(x) - u(x) v'(x) ) / v(x) ²

Then

w' (-5) = (u' (-5) v (-5) - u (-5) v' (-5) ) / v (-5)²

… = (2×6 - (-5)×4) / 6² = 32/36 = 8/9

(d) w(x) = u(x) / (u(x) + v(x) )

Chain and quotient rule:

w'(x) = (u'(x) (u(x) + v(x)) - u(x) (u(x) + v(x))' ) / (u(x) + v(x) )²

… = (u'(x) (u(x) + v(x)) - u(x) (u'(x) + v'(x))) / (u(x) + v(x) )²

Then

w' (-5) = (u' (-5) (u (-5) + v (-5)) - u (-5) (u' (-5) + v' (-5))) / (u (-5) + v (-5) )²

… = (2×((-5) + 6) - (-5)×(2 + 4)) / ((-5) + 6)²

… = (2×1 + 5×6) / 1² = 32

4 0

3 years ago

the accompanying graph shows the elevation of a certain region in new york state as a hiker travels along a trail.​

the accompanying graph shows the elevation of a certain region in new york state as a hiker travels along a trail.