Answer:
The area of APC is 70m². The area of triangle PMC is 35m².
Step-by-step explanation:
Let the area of triangle ABC be x.
It is given that AM is median, it means AM divides the area of triangle in two equal parts.
.....(1)
The point P is the midpoint of AB, therefore the area of APC and BPC are equal.
......(2)
The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.
.....(3)
The area of triangle APM is 35m².
Therefore the area of triangle ABC is 140m².
Using equation (2).
Therefore the area of triangle APC is 70m².
Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².
Therefore the area of triangle PMC is 35m².
To solve/simplify this all you have to do is group like terms (the x^2's with each other, the x's with each other, and the normal numbers, -8)
14x^2-8+5x-6x^2+2x
group the x^2 (add 14x^2 to -6x^2)
8x^2-8+5x+2x
group the x's together (add 5x and 2x together)
8x^2+7x-8
Your answer will be d) 8x^2+7x-8
Answer:
0.0016
Step-by-step explanation:
Batting average, p = 0.26
n = 7
x = 6
With p = 0.26 as success rate
1-p is equal to failure rate which is = 0.74
We have to solve this by using the binomial distribution formula.
P(X= x)
= nCx * p^x * (1-p)^(n-x)
P(X = 6)
=7C6 × 0.26^6 ×(1-0.26)^(7-6)
= 7 × 0.0003089 × 0..74¹
= 0.0016
So probability that he has exactly 6 hits in his next 7 bats is equal to 0.0016.
Answer:
0.2 or 20%
Step-by-step explanation:
If the times of arrival vary uniformly, there is an equal chance of an employee reporting at any given time between 8:40 and 9:30.
The range between 8:40 and 9:30 is 50 minutes.
The range between 9:00 and 9:10 is 10 minutes.
Therefore, the probability that a randomly chosen employee reports to work between 9:00 and 9:10 is:
The probability is 0.2 or 20%.
