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DedPeter [7]
3 years ago
12

Each snack at the concession stand is priced at $4.00. All of the snacks cost a total of $86.56. How many snacks will need to be

sold in order to make a minimum profit of $100.00?
Mathematics
1 answer:
Flauer [41]3 years ago
6 0

Answer:

25

Step-by-step explanation:

4x25=100

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Find a degree 4 polynomial having zeros -8,-1,4 and 5 and the coefficient of x^4 equal 1.
Keith_Richards [23]

Answer:

  x^4 -53x^2 +108x +160

Step-by-step explanation:

If <em>a</em> is a zero, then (<em>x-a</em>) is a factor. For the given zeros, the factors are ...

  p(x) = (x +8)(x +1)(x -4)(x -5)

Multiplying these out gives the polynomial in standard form.

  = (x^2 +9x +8)(x^2 -9x +20)

We note that these factors have a sum and difference with the same pair of values, x^2 and 9x. We can use the special form for the product of these to simplify our working out.

  = (x^2 +9x)(x^2 -9x) +20(x^2 +9x) +8(x^2 -9x) +8(20)

  = x^4 -81x^2 +20x^2 +180x +8x^2 -72x +160

  p(x) = x^4 -53x^2 +108x +160

_____

The graph shows this polynomial has the required zeros.

4 0
3 years ago
An urn contains 5 white and 10 black balls. A fair die is rolled and that number of balls is randomly chosen from the urn. What
galina1969 [7]

Answer:

Part A:

The probability that all of the balls selected are white:

P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\      P(A)=\frac{5}{66}=0.075757576

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516

Step-by-step explanation:

A is the event all balls are white.

D_i is the dice outcome.

Sine the die is fair:

P(D_i)=\frac{1}{6} for i∈{1,2,3,4,5,6}

In case of 10 black and 5 white balls:

P(A|D_1)=\frac{5_{C}_1}{15_{C}_1} =\frac{5}{15}=\frac{1}{3}

P(A|D_2)=\frac{5_{C}_2}{15_{C}_2} =\frac{10}{105}=\frac{2}{21}

P(A|D_3)=\frac{5_{C}_3}{15_{C}_3} =\frac{10}{455}=\frac{2}{91}

P(A|D_4)=\frac{5_{C}_4}{15_{C}_4} =\frac{5}{1365}=\frac{1}{273}

P(A|D_5)=\frac{5_{C}_5}{15_{C}_5} =\frac{1}{3003}=\frac{1}{3003}

P(A|D_6)=\frac{5_{C}_6}{15_{C}_6} =0

Part A:

The probability that all of the balls selected are white:

P(A)=\sum^6_{i=1} P(A|D_i)P(D_i)

P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\      P(A)=\frac{5}{66}=0.075757576

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

We have to find P(D_3|A)

The data required is calculated above:

P(D_3|A)=\frac{P(A|D_3)P(D_3)}{P(A)}\\ P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516

7 0
3 years ago
at the city museum child admission is $5.10 and adult admission is $9.60. on thursday 132 tickets were sold for a total sale of
Bad White [126]
C + a = 132.....a = 132 - c
5.10c + 9.60a = 898.20

5.10c + 9.60(132 - c) = 898.20
5.10c + 1267.20 - 9.60c = 898.20
5.10c - 9.60c = 898.20 - 1267.20
-4.50c = - 369
c = -369/-4.50
c = 82 <=== child tickets sold
5 0
3 years ago
SOMEONE HELP ME AGAINNN LOL
olya-2409 [2.1K]

Answer:

open circle

Step-by-step explanation:

the open circle does not include the number. this is what you want because the solution is not equal to the number

7 0
3 years ago
Read 2 more answers
HURRY ASAP WILL PICK BRAINLEST What is the value of 10 (4 minus 7) over negative (4 minus 1) ?
mariarad [96]

Answer:

10 its simple

Step-by-step explanation:

5 0
3 years ago
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