Answer:
49/8 is the value of k
Step-by-step explanation:
We have the system
x = -2y^2 - 3y + 5
x=k
We want to find k such that the system intersects once.
If we substitute the second into the first giving us k=-2y^2-3y+5 we should see we have a quadratic equation in terms of variable y.
This equation has one solution when it's discriminant is 0.
Let's first rewrite the equation in standard form.
Subtracting k on both sides gives
0=-2y^2-3y+5-k
The discriminant can be found by evaluating
b^2-4ac.
Upon comparing 0=-2y^2-3y+5-k to 0=ax^2+bx+c, we see that
a=-2, b=-3, and c=5-k.
So we want to solve the following equation for k:
(-3)^2-4(-2)(5-k)=0
9+8(5-k)=0
Distribute:
9+40-8k=0
49-8k=0
Add 8k on both sides:
49=8k
Divide both sides by 8"
49/8=k
A=(2x+1)/B
C=(5x-14)/B
AC=(2x+1)/B * (5x-14)/B
AC=(10x² - 23x - 14)/BE
The correct answer is water
A cube is a 3 dimensional object with 6 square faces. All its sides are the same length, there fore the volume is equal to
where s is the side length.
To solve for s, take the cube root of both sides.
![\sqrt[3]{s^3}= \sqrt[3]{ \frac{27}{64} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bs%5E3%7D%3D%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B27%7D%7B64%7D%20%7D%20%20)
feet
