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vredina [299]
3 years ago
10

What part is labeled a

Chemistry
1 answer:
Gnom [1K]3 years ago
7 0
How am I supposed to know, your not even showing the part lol
You might be interested in
3. Calculate the volume, in mL, of 100.0 g of alcohol, if the density is 0.79 g/mL.
Naya [18.7K]

Answer:

The answer is

<h2>126.58 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

<h3>volume =  \frac{mass}{density}</h3>

From the question

mass of alcohol = 100 g

density = 0.79 g/mL

The volume is

volume =  \frac{100}{0.79}  \\  = 126.58227848...

We have the final answer as

<h3>126.58 mL</h3>

Hope this helps you

4 0
4 years ago
What is this graph showing?
stepladder [879]

Explanation:

It's a distance-time graph showing the speed of an object

3 0
3 years ago
2 NaOH + H2SO4 → 2 H2O + Na2SO4<br> How many grams of water are produced from 203.50 grams of H2S04?
ddd [48]

Answer:

m_{H_2O}=74.8gH_2O

Explanation:

Hello there!

In this case, according to the given chemical reaction, it is possible to realize there is a 1:2 mole ratio of sulfuric acid to water; thus, given the mass of the former and its molar mass (98.07 g/mol), it is possible to determine the mass of produced water as shown below:

m_{H_2O}=203.50gH_2SO_4*\frac{1molH_2SO_4}{98.07gH_2SO_4}*\frac{2molH_2O}{1molH_2SO_4}  *\frac{18.02gH_2O}{1molH_2O}\\\\m_{H_2O}=74.8gH_2O

Regards!

6 0
3 years ago
If the density of a metal bar is 3.47 g/mL and volume is 30 mL, calculate the mass of the metal bar in grams (g). Show the steps
Hitman42 [59]

Answer:

m=104.1g

Explanation:

Hello,

In this case, considering that the density is considered as the quotient of the mass and volume:

\rho =\frac{m}{V}

We can easily compute the mass by solving for it as follows:

m=V*\rho =30 mL*3.47g/mL\\\\m=104.1g

Best regards.

7 0
3 years ago
Consider the reaction of magnesium metal with hydrochloric acid to produce magnesium chloride and hydrogen gas. if 4.40 mol of m
Georgia [21]
The balanced chemical equation for the above reaction is as follows ;
Mg + 2HCl —> MgCl2 + H2
The stoichiometry of Mg to HCl is 1:2
This means that 1 mol of Mg reacts with 2 mol of HCl
Equal amounts of both Mg and HCl have been added. One reagent is the limiting reactant and other reactant is in excess.
Limiting reactant is the reagent that is fully used up in the reaction and the amount of Product formed depends on the amount of limiting reactant present.
In this reaction if Mg is the limiting reactant, 4.40 moles of Mg should react with 4.40x2 -8.80 moles of HCl.
But only 4.40 moles of HCl present therefore HCl is the limiting reactant that reacts with 4.40/2 = 2.20 moles of Mg
Stoichiometry of HCl to MgCl2 is 2:1
Since HCl moles reacted -4.40 mol
Then MgCl2 moles formed are 4.40/2 = 2.20 mol of MgCl2
8 0
4 years ago
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