air blows at the base of circulation cells from high pressure to low pressure
Answer:
5
Explanation:
According to the Law of Conservation of Matter, the mass of the products in a chemical reaction must equal the mass of the reactants.
5O2 = 10 Oxygen atoms
In 2POx there must be 10 Oxygen atoms too. => x = 5
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Hope it can help you.
The number of electrons per second passing an ammeter if it reads 10 nA is 6.24 × 10⁹ electrons per second
Since our current reads 10 nA and we require the number of electrons per second passing through the ammeter, 10 nA = 1 × 10⁻⁹ C/s.
Since there are 1.602 × 10⁻¹⁹ C/electron, the number of electrons per second, n = current/electron charge
= 1 × 10⁻⁹ C/s ÷ 1.602 × 10⁻¹⁹ C/electron
= 1/1.602 × 10¹⁰ electrons
= 0.62422 × 10¹⁰ electrons per second
= 6.2422 × 10⁹ electrons per second
≅ 6.24 × 10⁹ electrons per second
So, the number of electrons per second passing an ammeter if it reads 10 nA is 6.24 × 10⁹ electrons per second
Learn more about electrons passing per second here:
brainly.com/question/14959684
Answer:
410.196 J/[kg*°C].
Explanation:
1) the equation of the energy is: E=c*m*(t₂-t₁), where E - energy (523 J), c - unknown specific heat of copper, m - mass of this copper [kg], t₂ - the final temperature, t₁ - initial temerature;
2) the specific heat of copper is:
![c=\frac{E}{m*(t_2-t_1)}; \ => \ c=\frac{523}{0.085*(45-30)}=\frac{523}{1.275}=410.196[\frac{J}{kg*C}].](https://tex.z-dn.net/?f=c%3D%5Cfrac%7BE%7D%7Bm%2A%28t_2-t_1%29%7D%3B%20%5C%20%3D%3E%20%5C%20c%3D%5Cfrac%7B523%7D%7B0.085%2A%2845-30%29%7D%3D%5Cfrac%7B523%7D%7B1.275%7D%3D410.196%5B%5Cfrac%7BJ%7D%7Bkg%2AC%7D%5D.)
