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vekshin1
3 years ago
6

If two atoms have an electronegativity difference of 1.3, what type of bond would form between them?

Chemistry
2 answers:
Debora [2.8K]3 years ago
5 0

Answer:

The correct answer is b polar covalent

Explanation:

When two atoms joined by covalent bond has difference in their electronegativities at that time polarity arise.

    When the electronegativity difference is low such as 1.3 then the polar bond formed by the two atoms are called polar covalent bond.For example H2O

 on the other hand polar bond formed by two atoms having high difference in their electronegativities is called ionic bond.For example NaCl.

zloy xaker [14]3 years ago
3 0

Answer:

a. polar covalent

Explanation:

Electronegativity is the tendency of an atom to attract a shared pair of electrons towards itself.

The higher the electronegativity, the more an atom attracts electrons towards itself.

The most commonly used method of calculation of electronegativity is done by Pauling's scale.

Cesium is the least electronegative (0.79), and fluorine is most electronegative (3.98)

Atoms that form bonds with high electronegativity difference among them form ionic bonds (metal and non-metal). If their electronegativity difference (Δ)=0, then they form non polar covalent bond.

  • Δ=0 : Non- polar covalent bond.
  • 0 < Δ < 1.7 : Polar covalent bond.
  • Δ = 1.7 : 50% ionic and 50% covalent bond
  • Δ > 1.7 : Ionic bond

The answer is a. polar covalent

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Answer:

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2. Answer: The bowling ball has equal amounts of potential and kinetic energy half way through the fall. At the half way point, half of the potential energy has been converted to kinetic energy.

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Hello!

The concentration of the final solution when a<span> chemistry teacher adds 50.0 mL of 1.50 M H2SO4 solution to 200 mL of water is 0,3 M

To calculate that, you'll need to use the dilution law, where initial and final concentrations are M1 and M2 respectively, and initial and final volumes are V1 and V2, as shown below. Keep in mind that the final volume is the sum of the 200 mL of water and the 50 mL of H</span>₂SO₄ that were added by the teacher. 

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