All categories

3 years ago

Does time stop in a black hole

Physics

2 answers:

lbvjy [14]3 years ago

4 0

Answer:

In standard GR, nothing exists at the center of a black hole. The center of a black hole is a singularity, and because GR fails at that point it is simply removed from the manifold. That means that the singularity is not part of spacetime.

To answer your question more realistically, we believe that GR is an approximate theory that fails well before you reach the center. Unfortunately, we have no good alternative theory with which to answer the question in the region where GR fails. We simply don’t have any data from that regime and it is very hard to formulate a good theory without data. So there very well could be time at the center, but we simply don’t have a good way to even guess.

kifflom [539]3 years ago

4 0

Answer:

Black hole is a region of space having a gravitational field so intense that no matter or radiation can escape

Actually time can't be stop.

although black hole slower a time

Explanation:

Time never cannot be stop totally.

You might be interested in

Which types of atoms usually become negative ions?

nalin [4]

Non metal ions gain electrons to become negative ions

5 0

4 years ago

What was the 2nd deepest ship wreck that James Cameron visited (from WWII)?

True [87]

Answer: :) i think its the t

8 0

2 years ago

A mass hanged on a spring scale. what is the force exerted by gravity on 700g ?

Ipatiy [6.2K]

Answer:

6.86 N

Explanation:

Applying,

F = mg............... Equation 1

Where F = Force exerted by gravity on the mass, m = mass, g = acceleration due to gravity

Note: The Force exerted by gravity on the mass is thesame as the weight of the body.

From the question,

Given: m = 700 g = (700/1000) = 0.7 kg

Constant: g = 9.8 m/s²

Substitute these values into equation 1

F = 9.8(0.7)

F = 6.86 N

6 0

3 years ago

Scientists experimenting with two charged objects of 2.56 x 10-6 C and 3.34 x 10-7 C displayed a repulsion of 2.26 x 10-3 N. How

Pachacha [2.7K]

Answer:

The objects were 1.8m apart.

Explanation:

We will start stating the Coulomb's Law. It says that:

$F_e=\frac{Kq_1q_2}{r^{2}}$

Where F_e is the electric force between the objects, q_1 and q_2 are the magnitude of the charge of the objects, r is the distance between them and K is the Coulomb's constant ( $K=8.9*10^{9} \frac{Nm^{2} }{C^{2} }$ in vacuum). Solving for the distance r we have:

$r=\sqrt{\frac{Kq_1q_2}{F_e} }$

Plugging the given values into this equation, we obtain:

$r=\sqrt{\frac{(8.9*10^{9}\frac{Nm^{2} }{C^{2} })(2.56*10^{-6}C)(3.34*10^{-7}C)}{2.26*10^{-3}N}}=1.8m$

In words, the two charged objects were 1.8m apart.

6 0

3 years ago

Read 2 more answers

A girl running around a circular track of radius 200 m completes one

kondor19780726 [428]

Answer:

v = 2 m/s

Explanation:

First, we find the angular velocity of the girl by using the following formula:

$Angular\ Velocity =\omega= \frac{Angular\ Distance\ Covered}{Time\ Taken}\\\\\omega = \frac{1\ revolution}{10\ min}\frac{1\ min}{60\ s}\frac{2\pi\ rad}{1\ revolution}\\\\\omega = 0.01\ rad/s$

Now, for the average velocity of the girl we can use the following formula:

$Average\ Velocity = V = r\omega\\V = (200\ m)(0.01\ rad/s)\\$

where,

r = radius = 200 m

therefore,

v = 2 m/s

4 0

3 years ago