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FinnZ [79.3K]
3 years ago
15

We have a long wire with a circular cross section and radius a = 2.40 cm. The current density in this wire is uniform, with a to

tal current of 3.00 A. Find the magnitude of the magnetic field at a distance of 0.72 cm from the center axis. Treat the wire as a cylinder.
Physics
1 answer:
Alika [10]3 years ago
7 0

Answer:

The magnitude of the magnetic field is 7.49x10⁻⁶T

Explanation:

The magnetic field is:

B=(\frac{\mu i}{2\pi R^{2} } )r

Where

i = current = 3 A

R = radius = 2.4 cm = 0.024 m

r = distance = 0.72 cm = 7.2x10⁻³m

Replacing:

B=(\frac{4\pi x10^{-7} *3}{2\pi *0.024^{2} } )*7.2x10^{-3}= 7.49x10^{-6} T

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After a fall, a 90 kg rock climber finds himself dangling from the end of a rope that had been 16 m long and 7.8 mm in diameter
Nesterboy [21]

Explanation:

Given that,

Mass of the rock climber, m = 90 kg

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Diameter of the rope, d = 7.8 mm

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\text{strain}=\dfrac{\Delta L}{L}\\\\\text{strain}=\dfrac{3.1\times 10^{-2}}{16}\\\\\text{strain}=0.00193

(b) The force acting per unit area is called stress.

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(c) The ratio of stress to the strain is called Young's modulus. So,

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8 0
3 years ago
1)what is the definition of moment of inertia?
OLEGan [10]

Answer:

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One formula that it is written in is I= mrx^{2}

Explanation:

As Bill Nye says, "Inertia is a property of matter. Objects that are not moving don't move unless they get pushed or pulled. Moving objects keep moving unless they get pushed or pulled. This feature of objects and materials is what we call inertia."

I would check out Dan Fullerton's concept

and Organic Chemistry

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Read 2 more answers
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Explanation:

a)current

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