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3 years ago

AP physics Will give brainliest to correct answer.

Physics

2 answers:

rjkz [21]3 years ago

6 0

Answer:

the 4th one

Explanation:

tangare [24]3 years ago

6 0

The answer is the 4th one

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Determine the magnitude as well as direction of the electric field at point A, shown in the above figure. Given the value of k =

Pavlova-9 [17]

Answer:

The magnitude of the electric field is $8.99*10^{12}N/C$ in the r direction.

Explanation:

The equation of the electric field is given by:

$|\vec{E}|=k\frac{q}{r^{2}}$

Where:

k is the Coulomb constant is $8.99 *10^{9}\: Nm^{2}C^{-2}$
q is the charge
r is the distance from A to q

$|\vec{E}|=8.99*10^{9}\frac{12.5}{0.11^{2}}$

$\vec{E}=9.29*10^{12} \vac{r} \: N/C$

Therefore, the magnitude of the electric field is $8.99*10^{12}N/C$ in the r direction.

I hope it helps you!

4 0

3 years ago

TRUE of FALSE: The human body responds to stressors by activating the nervous

melamori03 [73]

That is false I think sorry if its not correct

8 0

4 years ago

Only one symbol must be included in every circuit diagram. What symbol is it?

qaws [65]

Explanation :

A pictorial representation of a circuit is called as circuit diagram.

The three important components of a circuit are : Power source, wires and load.

Load means a bulb or any other electrical equipment and power source means a battery.

Out of three components, battery must be included in every circuit diagram because it provides voltage and without voltage there is no electric current.

The figure shows the symbol of a battery.

7 0

4 years ago

Question 2

Nostrana [21]

Answer:

in pretty sure the last one

8 0

4 years ago

A 60 cm diameter wheel accelerates from rest at a rate of 7 rad/s2. After the wheel has undergone 14 rotations, what is the radi

Mamont248 [21]

Answer:

$a=368.97\ m/s^2$

Explanation:

Given that,

Initial angular velocity, $\omega=0$

Acceleration of the wheel, $\alpha =7\ rad/s^2$

Rotation, $\theta=14\ rotation=14\times 2\pi =87.96\ rad$

Let t is the time. Using second equation of kinematics can be calculated using time.

$\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\\t=\sqrt{\dfrac{2\theta}{\alpha }} \\\\t=\sqrt{\dfrac{2\times 87.96}{7}} \\\\t=5.01\ s$

Let $\omega_f$ is the final angular velocity and a is the radial component of acceleration.

$\omega_f=\omega_i+\alpha t\\\\\omega_f=0+7\times 5.01\\\\\omega_f=35.07\ rad/s$

Radial component of acceleration,

$a=\omega_f^2r\\\\a=(35.07)^2\times 0.3\\\\a=368.97\ m/s^2$

So, the required acceleration on the edge of the wheel is $368.97\ m/s^2$ .

6 0

3 years ago