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Dahasolnce [82]
3 years ago
13

Una solución de 0.204 M de NaOH seutiliza para neutralizar 50 mL de una solución de H3PO4. Si se necesitaron 16.4 mL de la soluc

ión de NaOH para la neutralización completa, cual es laMolaridad de la solución de H3PO4.
Pliiiis ayudaaaa!!!
Biology
1 answer:
vfiekz [6]3 years ago
7 0

Answer: 0.05 M

Explanation:

Para responder esta pregunta, hay que tener en cuenta la Ley de Conservación de la Masa. <u>La misma indica que en una reacción química en un sistema cerrado, la masa total de las moléculas que participan permanece constante.</u> Esto significa que la masa utilizada en los reactivos es la misma que la masa de los productos generados.

En este problema, se cuenta con una solución de NaOH (hidróxido de sodio) tiene una molaridad de 0.204 (siendo la molaridad el número de moles por litro de solución) y se utilizan 16.4 mL de dicha solución para agregarla a 50 mL de una solución de H3PO4 (ácido fosfórico).

Entonces, ya que la masa de ambas soluciones no se pierde, podemos utilizar la ecuación de la Ley de Conservación de la Masa:

Concentración inicial x Volumen inicial = Concentración final x Volumen final.

Concentración inicial: 0.204 M

Volumen inicial: 16.4 mL

Concentración final: ?

Volumen final: 50 mL + 16.4 mL = 66.4 mL

Reemplazamos los valores en la ecuación:

0.204 M x 16.4 mL = Concentración final x 66.4 mL

La molaridad de la solución de H3PO4 es de 0.05 M.

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