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Furkat [3]
3 years ago
13

8. What is probability?​

Chemistry
1 answer:
nata0808 [166]3 years ago
6 0

Answer:

<em>In equipment reliability, the likelihood that a given event will occur</em>

Explanation:

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Uranium (VIII) Sulfide formula
tresset_1 [31]

Answer:

US₂

Explanation:

Uranium sulfide (US₂)

Uranium atomic symbol = U

Sulfur atomic symbol = S

Uranium valency = +4

Sulfur valency = -2

So;

Uranium sulfide (US₂)

8 0
3 years ago
Which of the following has the electron configuration [ar] 4s23d5 ?
nignag [31]

Answer:

Mn Manganese

Explanation:

5 0
3 years ago
Why might people continue to pursue space exploration in the future?
Lelechka [254]
Well people say the world's going to end soon so people need to find another planet to live on they're thinking about Mars at the moment
7 0
4 years ago
How do you determine the chemical reactivity for metals using the periodic table?
Lyrx [107]
You can know the metal with low reactivity and the metal with high reactivity from the periodic table, as in metals the Chemical reactivity increases by going down a group, because of the farther down group we go the easier of lose and gain of electrons or the easier the electrons to be given or taken, this caused the chemical reactivity be higher.
- and the chemical reactivity decreases as we go across the period because they want to give away valence electrons, they need more energy to get rid of them.
8 0
3 years ago
A student heats a sample of hydrate once, and the mass of the sample and the evaporating dish is 16.428 g. After a second heatin
jolli1 [7]

Answer:

12.371 g

Explanation:

Given :

m_{evaporating\ dish}=1.135\ g

m_{evaporating\ dish}+m_{Hydrate\ sample}=25.637\ g

m_{evaporating\ dish}+m_{First\ heated\ sample}=16.428\ g

m_{evaporating\ dish}+m_{Second\ heated\ sample}=13.266\ g

Mass of salt hydrate:

m_{evaporating\ dish}=1.135\ g

m_{evaporating\ dish}+m_{Hydrate\ sample}=25.637\ g

m_{Hydrate\ sample}=25.637-m_{evaporating\ dish}\ g=25.637-1.135\ g=24.502\ g

Mass of salt anhydrous:

m_{evaporating\ dish}=1.135\ g

m_{evaporating\ dish}+m_{Second\ heated\ sample}=13.266\ g

m_{Second\ heated\ sample}=m_{salt\ anhydrous}=13.266-m_{evaporating\ dish}\ g=13.266-1.135\ g=12.131\ g

Mass of water:

m_{water}=m_{Hydrate\ sample}-m_{salt\ anhydrous}=24.502-12.131\ g=12.371\ g

m_{water}=12.371\ g

4 0
4 years ago
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