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kozerog [31]
3 years ago
9

Based on what you have learned about intermolecular forces, would you say that matter is fundamentally attracted or repulsed by

other matter?
Chemistry
1 answer:
True [87]3 years ago
7 0

The attractive forces between the neighboring particles of a substance are known as intermolecular forces. The state of a substance relies upon the strength of the intermolecular forces among the molecules in a substance.  

There are three kinds of intermolecular forces, that is, the dipole-dipole forces, ion-dipole forces, and the London dispersion forces. On the basis of the kinds of intermolecular forces, it is concluded that the intermolecular forces primarily relies upon the nature of the molecule's bonding.  

Thus, on the basis of the nature of bonding between the associating atoms in a molecule one can know about the nature of intermolecular forces. On the basis of Newton's law of gravitation, all the physical bodies get fascinated towards each other, and it is known that each physical body comprises of matter. Thus, the matter is fundamentally attracted by other matter.  


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What is the term for temperature in a room reaching the point where all exposed surfaces in room ignite?
eimsori [14]

Answer:flashover

Explanation: flashover are event that occurs when all of the combustible materials in a room reach their ignition temperatures at the same time

3 0
3 years ago
(1) The solubility of Salt AB2(S) IS 5mol/dm^3.
Svetlanka [38]

Answer:

a. Ksp = 4s³

b. 5.53 × 10⁴ mol³/dm⁹

Explanation:

a. Obtain an expression for the solubility product of AB2(S),in terms of s.

AB₂ dissociates to give

AB₂ ⇄ A²⁺ + 2B⁻

Since 1 mole of AB₂ gives 1 mole of A and 2 moles of B, we have the mole ratio as

AB₂ ⇄ A²⁺ + 2B⁻

1 : 1 : 2

Since the solubility of AB₂ is s, then the solubility of A is s and that of B is 2s

So, we have

AB₂ ⇄ A²⁺ + 2B⁻

[s]        [s]    [2s]

So, the solubility product Ksp = [A²⁺][B⁻]²

= (s)(2s)²

= s(4s²)

= 4s³

b. Calculate the Ksp of AB₂, given that solubility is 2.4 × 10³ mol/dm³

Given that the solubility of AB is 2.4 × 10³ mol/dm³ and the solubility product Ksp = [A²⁺][B⁻]² = 4s³ where s = solubility of AB = 2.4 × 10³ mol/dm³

Substituting the value of s into the equation, we have

Ksp = 4s³

= 4(2.4 × 10³ mol/dm³)³

= 4(13.824 × 10³ mol³/dm⁹)

= 55.296 × 10³ mol³/dm⁹

= 5.5296 × 10⁴ mol³/dm⁹

≅ 5.53 × 10⁴ mol³/dm⁹

Ksp = 5.53 × 10⁴ mol³/dm⁹

6 0
3 years ago
A beaker contains a mixture of sand and small pebbles. what kind of mixture is this?
melomori [17]
Answer is: a beaker contains <span>heterogeneous mixture.

</span>

A heterogeneous mixture<span> have compounds that remain separate in the sample.</span>

Heterogeneous mixture is not uniform in composition (in this mixture different sand and small pebbles), but proportions of its components (in this mixture particles of different colors and size) vary throughout the sample.

3 0
3 years ago
How did Thomson show that cathode<br> rays are different from light?
Flura [38]

Answer:

They had a negative charge

Explanation:

5 0
3 years ago
A sample of kerosene has a mass of 36.4g. It’s volume is 45.6mL. What is the density of kerosene?
stira [4]

Answer:

<h2>Density = 0.8 g/cm³</h2>

Explanation:

The density of an object can be found using the formula

<h3>Density(\rho) =  \frac{mass}{volume}</h3>

From the question

mass of kerosene = 36.4 g

volume of kerosene = 45.6 mL

To find the density substitute the values into the above formula and solve

We have

<h3>Density =  \frac{36.4}{45.6}</h3>

= 0.7982

We have the final answer as

<h3>Density = 0.8 g/cm³</h3>

Hope this helps you

4 0
3 years ago
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