Ask question

Ask question

All categories

3 years ago

5

Calculate the volume of "dry" hydrogen that would be produced by one mole of magnesium at

1 answer:

kakasveta [241]3 years ago

5 0

Answer:The volume of H2 = 243mL = 0.243 L

Pressure of H2 gas collected = 745 mm

Pressure of H2 dry gas = P of H2 collected - vapor pressure of water = 745- 23.78 = 721.22 mm

= 721.22mm /760mm/atm

Temperature = 25C = 25+273= 298 K

Using the ideal gas equation

PV = nRT

or PV = (mass/molar mass) RT

(721.22/760)atm x 0.243L = (mass/ 2g/mol) x 0.0821L.atm/mol.K x 298K

Thus mass of H2 formed = 0.0188 g

Explanation:

You might be interested in

How many moles of H2O will be formed from the reaction of 80 g of

Roman55 [17]

Answer: 2 moles of $H_2O$ will be formed.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} NaOH=\frac{80g}{40g/mol}=2moles$

The balanced chemical equation is:

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

According to stoichiometry :

2 moles of $NaOH$ give = 2 moles of $H_2O$

Thus 2 moles of $NaOH$ give = $\frac{2}{2}\times 2=2moles$ of $H_2O$

Thus 2 moles of $H_2O$ will be formed.

4 0

3 years ago

You have two wires made of two different metals (metal A and metal B). Both wires are the same thickness and length. In one circ

kotegsom [21]

Answer: we don't have enough information to answer.

Explanation:

7 0

3 years ago

Would you classify silicone as a element or compound

bearhunter [10]

The answer is element

5 0

3 years ago

What is the use of a pedigree chart? Please do not answer wat a perigee chart is!.

FinnZ [79.3K]

Pedigree charts are used to see traits that are present in families or individuals. For example, it can be used see if certain diseases are running through someone's family and if that individual will inherit the disease.

8 0

3 years ago

Read 2 more answers

Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibri

lorasvet [3.4K]

Explanation:

The reaction equation will be as follows.

$CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)$

Calculate the amount of $CO_{2}$ dissolved as follows.

$CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}$

It is given that $K_{CO_{2}}$ = 0.032 M/atm and $P_{CO_{2}}$ = $1.9 \times 10^{-4}$ atm.

Hence, $[CO_{2}]$ will be calculated as follows.

$[CO_{2}]$ = $K_{CO_{2}} \times P_{CO_{2}}$

= $0.032 M/atm \times 1.9 \times 10^{-4}atm$

= $0.0608 \times 10^{-4}$

or, = $0.608 \times 10^{-5}$

It is given that $K_{a} = 4.46 \times 10^{-7}$

As, $K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}$

$4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}$

$[H^{+}]^{2}$ = $2.71 \times 10^{-12}$

$[H^{+}]$ = $1.64 \times 10^{-6}$

Since, we know that pH = $-log [H^{+}]$

So, pH = $-log (1.64 \times 10^{-6})$

= 5.7

Therefore, we can conclude that pH of water in equilibrium with the atmosphere is 5.7.

3 0

3 years ago