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Pachacha [2.7K]
3 years ago
15

The electron configuration of an element is electrons 1s^ 2 2s^ 2 2p^ 6 . Describe what most likely happens when an atom of this

element comes near an atom having seven valence
Chemistry
1 answer:
allochka39001 [22]3 years ago
4 0

Answer:

the atom is unreactive due to the completely filled electron configuration so the atom with the seven valence cannot involved in it

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Which list of elements consists of metalloids, only?
rewona [7]

Answer: D

Explanation: Boron (B), Silicon (Si), Germanium (Ge), Arsenic (As), Antimony (Sb), Tellurium (Te) and, Astatine (At) are all metalloids

4 0
3 years ago
Read 2 more answers
The vapor pressure of benzene is 73.03 mm Hg at 25°C. How many grams of estrogen (estradiol), C18H24O2, a nonvolatile, nonelectr
alexira [117]

Answer:

14.9802 grams of estrogen must be added to 216.7 grams of benzene.

Explanation:

The relative lowering of vapor pressure of solution containing non volatile solute is equal to mole fraction of solute.

\frac{p_o-p_s}{p_o}=\frac{n_2}{n_1+n_2}

Where:

p_o = Vapor pressure of pure solvent

p_s = Vapor pressure of the solution

n_1 = Number of moles of solvent

n_2 = Number of moles of solute

p_o = 73.03 mmHg

p_s= 71.61 mmHg

n_1=\frac{216.7 g}{78.12 g/mol}=2.7739 mol

\frac{73.03 mmHg-71.61 mmHg}{73.03 mmHg}=\frac{n_2}{2.7739 mol+n_2}

n_2=0.05499 mol

Mass of 0.05499 moles of estrogen :

= 0.05499 mol × 272.4 g/mol = 14.9802 g

14.9802 grams of estrogen must be added to 216.7 grams of benzene.

6 0
3 years ago
What volume in milliters would give 12.0 grams of NaOH from a 2.0 M NaOH solution?
zavuch27 [327]

Answer:

V = 150 mL

Explanation:

Hello!

In this case, since the molarity of a solution is computed via:

M=\frac{n}{V}

Whereas we are asked to compute the volume:

V=\frac{n}{M}

Thus, we first compute the moles in 12.0 g of NaOH as its molar mass is about 40.0 g/mol:

n=\frac{12.0g}{40.0g/mol}=0.3mol

Thus, at first instance, the volume liters is:

V=\frac{0.3mol}{2.0mol/L} \\\\V=0.15L

Which in milliliters is:

V=0.15L*\frac{1000mL}{1L}\\\\V=150mL

Best regards!

5 0
3 years ago
One mole of an ideal gas doubles its volume in a reversible isothermal expansion. (a) What is the change in entropy of the gas?
Andre45 [30]

Explanation:

The given data is as follows.

       n = 1 mol,     V_{f} = 2V_{i}

       Q = 1500 J,      R = 8.314 J/mol k

(a)    \Delta S = \frac{dQ}{dT}

And, according to the first law of thermodynamics

                \Delta E_{int} = Q - W

And, in an isothermal process the change in internal energy of the gas is zero.

Hence,    0 = Q - W

or,             W = Q

Expression for work done in an isothermal process is as follows.

                   W = nRT ln \frac{V_{f}}{V_{i}}

As W = Q, Hence expression for Q will also be given as follows.

            Q = nRT ln \frac{V_{f}}{V_{i}}

Now,  

        \Delta S = \frac{nRT ln \frac{V_{f}}{V_{i}}}{T}

        [/tex]\Delta S = nR ln \frac{V_{f}}{V_{i}}[/tex]

                      = nR ln \frac{2V_{i}}{V_{i}}

                       = nR ln 2

                        = 1 \times 8.314 \times 0.693

                        = 5.76 J/K

Therefore, change in entropy is 5.76 J/K.

(b)    As,  Q = nRT ln \frac{V_{f}}{V_{i}}

                   = nRT ln \frac{2V_{i}}{V_{i}}

                   = nRT ln 2

           T = \frac{Q}{nR ln 2}

              = \frac{1500}{1 \times 8.314 ln 2}

              = 260.4 K

Therefore, temperature of the gas is 260.4 K.

7 0
3 years ago
What is the density of an object with a volume of 12 mL and a mass of 38g?
Andreas93 [3]

Answer:

Hi im an online tutor and I can assist you with all your assignments. we have professionals in all fields. Check out our website https://toplivewriters.com

Explanation:

5 0
3 years ago
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