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zvonat [6]
2 years ago
9

Write the name of the alkane next to the drawing of the molecule.

Chemistry
1 answer:
Slav-nsk [51]2 years ago
7 0

Explanation:

  1. octane
  2. nonane
  3. butane
  4. methane
  5. propane
  6. ethane
  7. hexane
  8. pentane
  9. heptane
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3.5g of a Certain compound X, known to be made of carbon, hydrogen, and perhaps oxygen, and to have a molecular molar mass of 15
shutvik [7]

Answer:

C₅H₁₀O₅

Explanation:

1. Calculate the mass of each element in 2.78 mg of X.

(a) Mass of C

\text{Mass of C} = \text{5.13 g CO}_{2}\times \dfrac{\text{12.01 g C}}{\text{44.01 g }\text{CO}_{2}}= \text{1.400 g C}

(b) Mass of H

\text{Mass of H} = \text{2.10 g H$_{2}$O}\times \dfrac{\text{2.016 g H}}{\text{18.02 g H$_{2}$O}} = \text{0.2349 g H}

(c) Mass of O

Mass of O = 3.5 - 1.400 - 0.2349 = 1.87 g

2. Calculate the moles of each element

\text{Moles of C = 1400  mg C}\times\dfrac{\text{1 mmol C}}{\text{12.01 mg C }} = \text{116.6 mmol C}\\\\\text{Moles of H = 234.9 mg H} \times \dfrac{\text{1 mmol H}}{\text{1.008 mg H}} = \text{233.1 mmol H}\\\\\text{Moles of O = 1870 mg O} \times \dfrac{\text{1 mmol O}}{\text{16.00 mg O}} = \text{116 mmol O}

3. Calculate the molar ratios

Divide all moles by the smallest number of moles.

\text{C: } \dfrac{116.6}{116.6}= 1\\\\\text{H: } \dfrac{233.1}{116.6} = 1.999\\\\\text{O: } \dfrac{116}{116.6} = 1.00

4. Round the ratios to the nearest integer

C:H:O = 1:2:1

5. Write the empirical formula

The empirical formula is CH₂O.

6. Calculate the molecular formula.

EF Mass = (12.01 + 2.016  + 16.00) u  = 30.03 u

The molecular formula is an integral multiple of the empirical formula.

MF = (EF)ₙ

n = \dfrac{\text{MF Mass}}{\text{EF Mass }} = \dfrac{\text{150 u}}{\text{30.03 u}} = 5.00  \approx 5

MF = (CH₂O)₅ = C₅H₁₀O₅

The molecular formula of X is C₅H₁₀O₅.

8 0
3 years ago
Which is unique to the tire of the car
kvasek [131]

it is c trench marks

7 0
3 years ago
Read 2 more answers
An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is . The ballo
Liula [17]

The question is incomplete, here is a complete question.

An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is 13 ⁰C. The balloon is then taken outside, where the temperature is -9 ⁰C. Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly 1 atm. Be sure your answer has the correct number of significant digits.

Answer : The new volume of the balloon is 25.7 L

Explanation :

Charles's Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T

or,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1 = initial volume of gas = 27.8 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 13^oC=273+13=286K

T_2 = final temperature of gas = -9^oC=273+(-9)=264K

Now put all the given values in the above equation, we get:

\frac{27.8L}{286K}=\frac{V_2}{264K}

V_2=25.7L

Therefore, the new volume of the balloon is 25.7 L

3 0
2 years ago
PLEASE HELP:
klio [65]

Answer:

Oil spills

Explanation:

I've done it before

5 0
3 years ago
In the chemical reaction, how many grams of nitrogen are needed to completely react with 24.3 grams of hydrogen
vlabodo [156]

Answer:

112.540 gram of N2

Explanation:

From the balanced chemical equation

N2+3H2----->2NH3

It means that 1 mole of Nitrogen needs 3 moles of hydrogen

In term of mass,we can say that

6.048 gram of H2 needs 28.01 gram of N2

or, 1 gram of H2 needs (28.01/6.048) gram of N2

and 24.3gram of H2 needs (24.3*28.01/6.048) gram of N2

=112.540 gram of N2

5 0
3 years ago
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