Answer:
1 COSMETICS WITH MICROBEADS
2 COFFEE CAPSULES
3 WET WIPES
Explanation:
1.Plastic microbeads began to be introduced in cosmetics, toiletries and cleaning products in the 1970s, but it wasn’t until the 1990s that brands began to incorporate them in a massive way. Toothpastes, creams, lotions, shampoos and detergents began to include microbeads as the great innovation of the time for achieving an abrasive effect, replacing the nature-based materials in use until then.
2 Capsule coffee machines have revolutionized the breakfasts of millions of people, offering a convenient and practical option for preparing an espresso or latte with the same quality one finds in a café. Data from 2017 indicate that 29% of US coffee consumers use these machines, a figure that continues to grow.
3They started off being an invaluable aid for fathers and mothers when facing the messy moment of their baby’s diaper change, but soon they began to be reinvented as deodorants, cleansers, disinfectants and hand soap substitutes, and even as toilet paper for adults. Wet wipes have become a common item in many homes, but with a dramatic consequence: they help to create fatbergs, immense accumulations that block the sewerage networks and that are composed of 93% non-degradable wipes, together with fat, condoms and other similar items thrown into the toilet.
The illumination of the book is found to be approximately equal to 15 lx.
Option 1.
Explanation:
Luminous flux is the measure of power of the light emitted from a source and illumination is the property of the light to illuminate a given surface when it falls on the surface. So the measure of the region the light flux illuminates the surface is termed as illumination.
As here the luminous flux is given as 1759 lm and the distance of the object which has to be illuminated is placed 3 m away from the source ,the illumination is found to be directly proportional to the luminous flux and inversely proportional to the square of the distance between them
So, the illumination of the book is found to be approximately equal to 15 lx.
The average kinetic energy of an atom in helium gas at temperature T is given by,
K.E=
here, K is botzmann constant =1.38×10⁻²³ m² kg s⁻² K⁻¹
Given, K.E= 6.21×10⁻²¹ J
Substituting the values,
T= 300 K
Therefore, at temperature 300 K the average kinetic energy of the atom in helium gas is 6.21×10⁻²¹ J.
P=4800kgm/s
As
p=mΔv
where p is momentum, m is mass and v is velocity
Given values is
m =1200kg
Δv= 17m/s-13m/s=4m/s
Now
p=mΔv
p=(1200kg)*(4m/s)
p=4800kgm/s
