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marissa [1.9K]
3 years ago
15

what is the total distance traveled by a bike rider who rides for three hours at 40 km/hr and then two more hours at 50 km/hr?

Physics
1 answer:
marta [7]3 years ago
4 0

Answer:

220 km

Explanation:

3 hours at 40 km/hr

40 km = 1 hour

40 km times 3 = 120 km

2 hours at 50 km/hr

50 km = 1 hour

50 times 2 = 100 km

Total distance

120 km + 100 km = 220 km

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belka [17]

Answer:

25.  Approximately 8.1 meters

26. North 1.31 km, and East 2.81 km

Explanation:

25.

Notice that the displacements: 6 meters east and 5.4 south create the legs of a right angle triangle. The hypotenuse of that triangle will be the distance (d) needed to cover in order to get the ball in the hole in one putt. That is:

d=\sqrt{6^2+5.4^2} =\sqrt{65.16} \approx 8.072\,\,\,m

which can be rounded to 8.1 m.

26.

Notice that the 3.1 km at an angle of 25 degrees north of east, is the hypotenuse of a right angle triangle that has for legs the east and north components of that distance.

We can find the leg corresponding to the east displacement using the cosine function (that relates adjacent side with hypotenuse):

east\,\, comp=3.1 * cos(25^o)\approx 2.809\,\,km

and we can calculate the north component using the sine function that relates the opposite side to the angle with the hypotenuse.

north\,\,component = 3.1 * sin(25^o) \approx 1.31 \,\,km

6 0
3 years ago
Jose gets up from his seat on the bus to move closer to the front. Just as he begins to walk forward, the bus stops at a light.
aleksklad [387]

Answer:

She falls forward

Explanation:

Dunno, just factss

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2 years ago
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Which of the following terms corresponds to #2 on the image?
Mila [183]

Answer:

Trough

Explanation:

cuz physics you see

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Two postal delivery workers have different routes. They both travel from the post office, to neighborhoods to deliver mail, and
SOVA2 [1]

they travel the same distance

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If a positive test charge is placed in an electric field, what is the direction of the force on the test charge?
svetlana [45]

Explanation:

If a positive test charge is placed in an electric field, it will exert the force in the test charge in the direction of electric field vector. We know that the direction of electric field is given by electric field lines. The field lines for a positive charge is outwards. The electric force acting on the charge is given by :

F = q E

Hence, this is the required solution.

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3 years ago
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