ΔH<span> for the reaction = [sum of heat of formation for products] - [sum of heat of formation for reactants]

-6534 = [(12)(-393.5) + (6)(-285.8)] - (2X)

-6534 = [(-4722) + (-1714.8)] - 2X

-6534 = -6436.8 - 2X

-6534 + 6436.8 = -2X

-</span>97.2 = -2X<span>

then, divide each side by two to cancel out the numerical coefficient.

x = +48.6 kJ, which is the heat of formation for benzene.</span>

7 0

3 years ago

URGENT! PLEASE ANSWER!!

Marrrta [24]

Answer:

Explanation:

The answer is obvious from the given figure

7 0

3 years ago

Determine the stopping location of the prize wheel. At this moment it is centered on the number 11. It is spinning at a rate of

Goshia [24]

Answer:

The wheel spins for 11.43s. The number cannot be determined.

Explanation:

We know that initial velocity is 124.4 rpm = 13.027137522 rad/s, acceleration is -1.14 rad/s^2, and final velocity is assumed to be 0 rad/s. We are asked to find t and displacement. We use the equation $\omega=\omega_0+\alpha t$ where $\omega=0 rad/s$ , $\omega_0=13.027 rad/s$ , $\alpha=-1.14rad/s^2$ , and $t=?$ .