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dusya [7]
3 years ago
11

when a man throws a stone in the direction of maximum range the stone rises to a height of 20m . what is the range and how long

is the stone in air​
Physics
1 answer:
jeyben [28]3 years ago
3 0

Answer:

50m

Explanation:im just smart thank me later

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A model rocket weighing 4.9 N launches from a pad. How much work does the little rocket engine do in the first 4 meters
USPshnik [31]

Answer:

 Work done by the little rocket engine = 19.6 Joules.

Explanation:

 We know that work = force x displacement.

 Force = weight of rocket = 4.9 N

 Displacement = 5 meter.

 So work done by the little rocket engine = Weight of rocket x displacement.

  Work done by the little rocket engine = 4.9 x 4 = 19.6 J

    Work done by the little rocket engine = 19.6 Joules.

5 0
3 years ago
Neptunium. In the fall of 2002, scientists at Los Alamos National Laboratory determined that the critical mass of neptunium-237
Paladinen [302]

Answer:

Radius = 9.0216 cm

Explanation:

Given that:

The critical mass of neptunium-237 = 60 kg

Also, 1 kg = 1000 g

So mass = 60000 g

Density = 19.5 g/cm³

Volume = ?

So, volume:  

Volume=\frac {{Mass}}{Density}  

Volume=\frac {60000\ g}{19.5\ g/cm^3}  

The volume of the material = 3076.92308 cm³

The expression for the volume of the sphere is:

V=\frac {4}{3}\times \pi\times {(radius)}^3

3076.92308=\frac{4}{3}\times \frac{22}{7}\times {(radius)}^3

\frac{4}{3}\times \frac{22}{7}\times {(radius)}^3=3076.92308

88\times {(radius)}^3=64615.38468

{(radius)}=\sqrt[3]{\frac{64615.38468}{88}}

<u>Radius = 9.0216 cm</u>

4 0
4 years ago
The decibel level of an orchestra is 90 db, and the violin section achieves a level of 80 dB. How does the sound intensity from
skad [1K]

Answer:

The difference in the decibel corresponses to a constant difference in the loudness perceived.

The refore the sound intensity from the orchestra is like 100 times that of the violin.

Explanation:

4 0
3 years ago
Ajani is trying to experimentally measure Planck's constant h. He does this by shining different wavelengths of monochro- matic
olga_2 [115]

Answer:

h = 1.01 x 10⁻³⁴ J.s

Explanation:

The energy applied by the voltage must be equal to the energy associated with the wavelength of light:

eV = \frac{hc}{\lambda}\\

where,

e = charge on electron = 1.6 x 10⁻¹⁹ C

V = stopping potential

h = Planck's Constant = ?

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of light

For λ = 400 nm = 4 x 10⁻⁷ m, V = 0.7 V:

(1.6\ x\ 10^{-19}\ C)(0.7\ V) = \frac{h(3\ x\ 10^8\ m/s)}{4\ x\ 10^{-7}\ m}\\

h = 1.49 x 10⁻³⁴ J.s

For λ = 500 nm = 5 x 10⁻⁷ m, V = 0.2 V:

(1.6\ x\ 10^{-19}\ C)(0.2\ V) = \frac{h(3\ x\ 10^8\ m/s)}{5\ x\ 10^{-7}\ m}\\

h = 0.53 x 10⁻³⁴ J.s

Taking average of both values:

h = \frac{(0.53+1.49)\ x\ 10^{-19}\ J.s}{2}

<u>h = 1.01 x 10⁻³⁴ J.s</u>

3 0
3 years ago
If the frequency of an electromagnetic wave increases, does the number of waves passing by you increase, decrease, or stay the s
jarptica [38.1K]

Answer:

option(d)

Explanation:

The frequency of a wave is the property of the source of wave.

The velocity of all the electromagnetic waves is same as the speed of light. It only changes as the light passes through one medium to another.

The frequency is defined as the number of waves coming out from the source in 1 second.

As the frequency of wave increases, the number of wave coming per second increases.

So, the number of waves passing by increases but the speed remains same.

Option (d)

3 0
3 years ago
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