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dusya [7]
3 years ago
11

when a man throws a stone in the direction of maximum range the stone rises to a height of 20m . what is the range and how long

is the stone in air​
Physics
1 answer:
jeyben [28]3 years ago
3 0

Answer:

50m

Explanation:im just smart thank me later

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Simple the answer is A and only 2 ones
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It is correct to say that impulse is equal toA) momentum.B) the change in momentum.C) the force multiplied by the distance the f
goldenfox [79]

Answer:

B) the change in momentum

Explanation:

Impulse is defined as the product between the force exerted on an object (F) and the contact time (\Delta t)

I=F \Delta t

Using Newton's second law (F = ma), we can rewrite the force as product of mass (m) and acceleration (a):

I=(ma) \Delta t

However, the acceleration is the ratio between the change in velocity (\Delta v) and the contact time (\Delta t): a=\frac{\Delta v}{\Delta t}, so the previous equation becomes

I=m \frac{\Delta v}{\Delta t}\Delta t

And by simplifying \Delta t,

I=m \Delta v

which corresponds to the change in momentum of the object.

8 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs.
Sergeu [11.5K]

Answer:

Sound energy to electric energy - a person talking into a microphone

Radiant energy to electric energy - sunlight falling on solar panels

Gravitational potential energy to motion energy - a ball dropped from a height

Explanation:

A person talking is the sound energy and going into an electric phone

Sunlight or Radiant energy falls onto the solar panels creating electric energy

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6 0
3 years ago
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Two parallel slits are illuminated by light composed of two wavelengths. One wavelength is λA = 622nm. The other wavelength is λ
Sergio039 [100]

Answer:

\lambda_{B}=414.67 nm

Explanation:

In this question we have given

\lambda_{A}=622nm

we have to find

\lambda_{B}=?

We know that

optical path difference for bright fringe is given as=n\lambda

Here,

n is order of fringe

and optical path difference for dark fringe is given as=(n+.5)\lambda

since the light with wavelength \lambda_{A} produces its third-order bright fringe at the same place where the light with wavelength \lambda_{B} produces its fourth dark fringe  

it means

optical path difference for 3rd order bright fringe= optical path difference for forth order dark fringe

Therefore,

3\lambda_{A}=(4+.5)\lambda_{B}...............(1)

Put value of \lambda_{A} in equation (1)

3 \times 622=(4+.5)\lambda_{B}

1866=4.5\lambda_{B}

\lambda_{B}=414.67 nm

3 0
3 years ago
A 2.50 kg ball is attached to a 3.00 m bar and swung in a vertical circle. If the ball does not leave the circular loop, what mi
dezoksy [38]

Answer:

5.42 m/s

Explanation:

At minimum speed, the tension in the bar will be 0 when the ball is at the top of the arc, so the only force is gravity pulling down.

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v = 5.42 m/s

6 0
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