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3 years ago

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20 pts.

2 answers:

RUDIKE [14]3 years ago

6 0

The cup is acted upon by an unbalanced force which is the cars acceleration, but before it was an object at rest that stayed at rest. This jet propels their body forward.

KIM [24]3 years ago

3 0

Answer:

The cup is acted upon by an unbalanced force which is the acceleration of the car, but before it was an object at rest that stayed at rest.

Explanation:

Newton's first law of motion states, "if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force."

Since the cup is at rest while sitting on top of the car, it stays at rest as the car begins to move. Since the car is accelerating and the cup is not, the cup falls off of the car.

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Isla made ice by putting water in the freezer. Freezing is an example of (2 points)

SSSSS [86.1K]

Answer:

a physical change

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3 years ago

Read 2 more answers

A train travels 8.81 m/s in a -51.0° direction.

Bad White [126]

The displacement of the train after 2.23 seconds is 25.4 m.

<h3>Resultant velocity of the train</h3>

The resultant velocity of the train is calculated as follows;

R² = vi² + vf² - 2vivf cos(θ)

where;

θ is the angle between the velocity = (90 - 51) + 37 = 76⁰

R² = 8.81² + 9.66² - 2(8.81 x 9.66) cos(76)

R² = 129.75

R = √129.75

R = 11.39 m/s

<h3>Displacement of the train</h3>

The displacement of the train is the change in position of the train after a given period of time.

The displacement is calculated as follows;

Δx = vt

Δx = 11.39 m/s x 2.23 s

Δx = 25.4 m

Thus, the displacement of the train after 2.23 seconds is 25.4 m.

Learn more about displacement here: brainly.com/question/2109763

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5 0

2 years ago

The length and width of a rectangular room are measured to be 3.92 ± 0.0035 m and 3.15 ± 0.0055 m. In this problem you can appro

Pavel [41]

Answer:

A) $A=12.2480\ m^2$

B) $12.2480\pm 0.1029\ m^2$

Explanation:

<u>Given:</u>

Length of the room $l= 3.92 ± 0.0035$

Width of the room $w= 3.15 ± 0.0055$

A) Let A be the area of the room

$A=l\times w\\A=3.92\times3.15\\A=12.2480\ \rm m^2$

B)We will calculate uncertainty in each dimension

%uncertainty in length $=\dfrac{0.0035}{3.92}\times 100=0.0892\ %$

%uncertainty in width = $\dfrac{0.0055}{3.15}\times 100=0.0174%$

The uncertainty in area will be sum of uncertainty in length and width

%uncertainty in Area= %uncertainty in length + %uncertainty in width

%uncertainty in Area $=0.0892\ % + 0.0174\ %$

%uncertainty in Area=0.0106

Uncertainty in Area $=0.0106\times 12.2480=0.1029\ \rm m^2$

There Area is $12.2480 ± 0.1029\ \rm m^2$

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3 years ago

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MaRussiya [10]

You are right :P

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3 years ago

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What is the mass of a liquid having a density of 1.50 g/ml and a volume of 3.5 liters?

PIT_PIT [208]

We know the formula for density = Mass/ volume

So Mass, M = Volume * Density

Volume = 3.5 L= 0.0035 $m^3$

Density = 1.50 g/ml = 1500 $kg/m^3$

Mass, M = 0.0035*1500 = 5.25 kg

So mass of liquid having density 1.50 g/ml and volume 3.5 liters is 5.25 kg.

6 0

4 years ago