The formula for finding a gradient is
y2-y1/x2-x1.
So in your case it will be the following:
If point

is on the unit ircle, then:

Since, the point is in the second quadrant, x is negative.
Thus,

Part A:

Therefore,

.
Part B:

Therefore,
Answer:
n = 3
Step-by-step explanation:
8n - (3n + 4) = 11
8n - 3n - 4 = 11
5n = 11 + 4
5n = 15
n = 3
Answer:
E. -8/3
F. 8/3
Step-by-step explanation:
9x^2-64=0
Add 64 to each side
9x^2-64+64 = 0+64
9x^2 =64
Divide each side by 9
9x^2/9 = 64/9
x^2 = 64/9
Take the square root of each side
sqrt(x^2) = ±sqrt(64/9)
We know that sqrt(a/b) = sqrt(a)/sqrt(b)
x = ±sqrt(64)/sqrt(9)
x = ± 8/3
Answer:
m
Step-by-step explanation: