3 years ago

How do you think you results would be affected if using K2Cr2O7/H2SO4 as the oxidizing agent instead of KMnO4

Chemistry

1 answer:

makkiz [27]3 years ago

3 0

Answer:

Due to weak oxidizing agent.

Explanation:

In my opinion the results would be affected if using K2Cr2O7/H2SO4 as the oxidizing agent instead of KMnO4 because K2Cr2O7/H2SO4 is weak oxidizing agent as compared to KMnO4. An oxidizing agent is a substance that has the ability to oxidize other substances means that accept their electrons so that's why the results of strong oxidizing agent is different than weak oxidizing agent.

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a cube of iron (cp = 0.450 j/g•°c) with a mass of 55.8 g is heated from 25.0°c to 49.0°c. how much heat is required for this pro

krek1111 [17]

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3 years ago

Read 2 more answers

The ion p3− has _____ protons and _____ electrons. enter your answers as integers separated by a comma.'

katrin2010 [14]

The symbol $P$ is for phosphorus having atomic number 15. That means it has $15 protons and 15 electrons$ in its neutral state.

The given symbol $P^{3-}$ has a -3 charge that means it has gained 3 electrons so, the number of electrons in the $P^{3-}$ is: $15+3 = 18$ . The number of protons will remain same that is the number of protons = 15.

So, the ion $P^{3-}$ has $15 protons and 18 electrons$ that gives $15-18=-3$ charge on the $P^{3-}$ ion.

So, the answer is $15 , 18$ .

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