1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
umka2103 [35]
3 years ago
8

What is the mass of 3.0 x 10^23 atoms of neon

Chemistry
1 answer:
anzhelika [568]3 years ago
8 0


3.0e23 atoms Ne

"E" means 10^

Then we multiply it by a mole of Ne. By the definetion of a mole, it is always 6.022e23 atoms of an element.

So now, we do this:

3.0e23 atoms Ne x (1 mol Ne / 6.022e23 atoms Ne)

After that, we use molar mass. A mole of Neon is equal, in terms of grams, to its avg. atomic mass. This goes true for any element.

It ends up like this:

3.0e23 atoms Ne x (1 mol Ne / 6.022e23 atoms Ne) x (20.1797 g Ne / 1 mol Ne)

Now cancel out the "atoms Ne" and "1 mol Ne"

You end up with a grand total of...
*plugs everything into a calculator*

10.05298... g Ne.

We need to round to 2 sig. figs. (3.0) so now it's....

10 g Ne.

Note that this method can only be used for converting atoms of an element to mass in grams.
Source(s):
A periodic table for the atomic mass of neon.
A chemistry textboook
A chemistry class.
You might be interested in
Pls just help me out the vid is 6 Chemical Reactions That Changed History; need help on no.6. I DON’T EVEN KNOW HOW TO SOLVE IT
GREYUIT [131]

Explanation:

HCL you can do it yourself .try again

4 0
3 years ago
What is the balance equation for
murzikaleks [220]

1st one

2_2_2

2nd one

3_1_1_3

i looked it up

7 0
2 years ago
How can magnetic force be exerted on objects?
just olya [345]
I think the answer is : 1
8 0
2 years ago
What is the endpoint of a titration?Select one:When there is no acid and all base.When the amount of acid and base are equal.Whe
user100 [1]

Answer:

The correct option is: When the amount of acid and base are equal

Explanation:

Titration is an analytic method that is used to determine the concentration of an<em> unknown solution</em>, called <em>titrand</em>.

In this method, standard solution of known concentration, called <em>titrant</em>, is taken in the burette and added drop-wise to the titrand solution in the flask, until the endpoint is reached.

In case of an acid-base titration, a <em>pH indicator</em> is used, which changes the color of the solution when the endpoint is reached.

<u>The </u><u>endpoint</u><u> indicates the </u><u>equivalence point</u><u> of an acid-base titration, where the </u><em><u>concentration of the acid and base is equal</u></em><u>. </u>

<u>Therefore, the </u><u>correct option</u><u> is: </u><u>When the amount of acid and base are equal</u>

3 0
3 years ago
What could J.J. Thomson conclude from his experiments?
KonstantinChe [14]

Answer:C, atoms must balance positive and negative particles.

Explanation: Got it correct on edgenuity.

6 0
3 years ago
Other questions:
  • What structure do insects have for breathing (A) gills (B) tracheae (C) skin (D) lungs
    10·1 answer
  • Classify each of the molecules given below by molecular shape.
    15·1 answer
  • Two parents who are both GG for a gene are crossed. what is the genetic makeup of the offspring.
    10·2 answers
  • Give reason:
    8·1 answer
  • How are the particles of butterfat made smaller so that the mixture is homogenized?
    10·1 answer
  • Thermal radiation emitted by objects allows us to feel infrared<br> energy as _____
    7·1 answer
  • A 0.3146-g sample of a mixture of nacl(s) and kbr(s) was dissolved in water. the resulting solution required 55.00 ml of 0.08765
    12·1 answer
  • Which symbol represents an atom in the ground state with the most stable valence electron configuration?
    14·2 answers
  • Please work out all the problems on this page, no links, no i don't knows please do not take advantage of me or my points please
    10·2 answers
  • Need help with this
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!