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Mumz [18]
3 years ago
12

How many moles of CO2 are produced

Chemistry
1 answer:
Sergio039 [100]3 years ago
6 0

Answer:

30.0 mol CO₂

Explanation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

To answer this problem we need to convert moles of C₃H₈ into moles of CO₂: We'll do that by using the <u>stoichiometric coefficients</u>, using a conversion factor that has C₃H₈ moles in the denominator and CO₂ moles in the numerator:

10.0 mol C₃H₈ * \frac{3molCO_2}{1molC_3H_8} = 30.0 mol CO₂

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A gas occupies 200ml at a temperature of 26 degrees Celsius and 76mmHg pressure. Find the volume at -3degree Celsius with the pr
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Answer:

184.62 ml

Explanation:

Let p_1, v_1, and T_1 be the initial and p_2, v_2, and T_2 be the final pressure, volume, and temperature of the gas respectively.

Given that the pressure remains constant, so

p_1=p_2 ...(i)

v_1 = 200 ml

T_1= 26 ^{\circ}C = 273+26 =299 K

T_2= 3 ^{\circ}C = 273+3 =276 K

From the ideal gas equation, pv=mRT

Where p is the pressure, v is the volume, T is the temperature in Kelvin, m is the mass of air in kg, R is the specific gas constant.

For the initial condition,

p_1v_1=mRT_1 \\\\mR= \frac{p_1v_1}{T_1}\cdots(ii)

For the final condition,

p_2v_2=mRT_2 \\\\mR= \frac{p_2v_2}{T_2}\cdots(iii)

Equating equation (i), and (ii)

\frac{p_1v_1}{T_1}=\frac{p_2v_2}{T_2}

\frac{v_1}{T_1}=\frac{v_2}{T_2}  [from equation (i)]

v_2=\frac{T_2}{T_1} \times v_1

Putting all the given values, we have

v_2=\frac{276}{299} \times 200 = 184.62 \; ml

Hence, the volume of the gas at 3 degrees Celsius is 184.62 ml.

7 0
3 years ago
Which of the following is the correct name for MgCl2?
Studentka2010 [4]

Answer:

Magnesium dichloride

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You're provided a 0.50 M solution of HCl. How many moles of HCl are present in 25 ml of this solution? ​
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Explanation:

(0.50 mol/L)(0.025 L) = 0.0125 moles of HCl

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Mg₃N₂
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