Need the answer:) :)

Mathematics

1 answer:

user100 [1]2 years ago

4 0

1/y^3 is your answer

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Suppose that a recent article stated that the mean time spent in jail by a first-time convicted burglar is 2.5 years. A study wa

Sladkaya [172]

Answer:

The null hypothesis is $H_0: \mu = 2.5$ .

The alternative hypothesis is $H_1: \mu > 2.5$

Step-by-step explanation:

Suppose that a recent article stated that the mean time spent in jail by a first-time convicted burglar is 2.5 years.

At the null hypothesis, we test if the mean is of 2.5 years, that is:

$H_0: \mu = 2.5$

A study was then done to see if the mean time has increased in the new century.

At the alternative hypothesis, we test if the mean has increased, that is, if it is above 2.5 years. So

$H_1: \mu > 2.5$

8 0

2 years ago

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Anna35 [415]

Answer:

Step-by-step explanation:

80-37 = 43

7 0

1 year ago

Find the equation of a line that goes through the points (-3,5) and (5,-11)

Rasek [7]

$(\stackrel{x_1}{-3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{-11}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-11}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{(-3)}}}\implies \cfrac{-16}{5+3}\implies \cfrac{-16}{8}\implies -2$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{-2}(x-\stackrel{x_1}{(-3)}) \\\\\\ y-5-2(x+3)\implies y-5=-2x-6\implies y=-2x-1$