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Sergeeva-Olga [200]
3 years ago
15

Please answer all of these questions and you will get the brain list

Physics
1 answer:
pogonyaev3 years ago
6 0

Answer:

1=900j

2=140j

3=5m

Explanation:

1,

work=force×displacement

w=450×2

w=900j

2,

w=f×s

w=70×2

w=140j

3,

w=f×s

200=40×s

200/40=s

s=5m

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zmey [24]
The answer is C
All other statements are correct but C
6 0
4 years ago
An airplane has an effective wing surface area of 17.0 m2 that is generating the lift force. In level flight the air speed over
olga_2 [115]

To solve this problem it is necessary to apply the equations given from Bernoulli's principle, which describes the behavior of a liquid moving along a streamline. Mathematically this expression can be given as,

P_1 + \frac{1}{2}\rho*v_1^2 + P_2 + \frac{1}{2}*\rho*v_2^2=0

Where,

P_i = Pressure at each state

\rho= Density

v_i = Velocity

Re-organizing the expression we can get that

P_1 - P_2 = \frac{1}{2}\rho (v_2^2 - v_1^2)

Our values are given as

v_1 = 40m/s

v_2 = 55m/s

\rho_{water} = 1.2kg/m^3 \rightarrow Normal Conditions

Replacing we have,

P_1 -P_2 = \frac{1}{2}*1.2*(55^2-40^2)

P_1 - P_2 = 855Pa

If we consider that there is a balance between the two states, the Force provided by gravity is equivalent to the Support Force, therefore

F_l = F_g

Here the lift force is the product between the pressure difference previously found by the effective area of the aircraft, while the Force of gravity represents the weight. There,

F_g = W

F_l = (P_2-P_1)A

Equating,

(P_1 - P_2)*A = W

W = 855*17

W = 14535 N

Therefore the weight of the plane is 14535N

3 0
3 years ago
A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 16.0 when the han
slava [35]

There are mistakes in the question as the unit of speed and height is not mention here.The correct question is here

A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 16.0m/s when the hand is 1.80m above the ground.How long is the ball in the air before it hits the ground? (The student moves her hand out of the way.)

Answer:

t=3.37s

Explanation:

Given Data

As we have taken hand at origin and positive upward

So given data are

y_{i}=0m\\y_{f}=-1.80m\\v_{i}=16.0m/s\\a=g=9.8m/s^{2}

To find

time taken by the ball before it hits the ground

Solution

By using the common kinematic equation

y_{f}=y_{i}+v_{i}t+0.5at^{2}

Put the given values and find for t

So

-1.80=0+16.0t+(0.5*(-9.8)t^{2} )\\-1.80=16.0t-4.9t^{2}\\ 4.9t^{2}-16.0t-1.80=0

Apply quadratic formula to solve for t

t=\frac{-(-16.0)+\sqrt{(-16)^{2}+4(4.9)(-1.80)} }{2(4.9)}\\ t=3.37s

4 0
4 years ago
If an object that weighs 20 N is lifted from the ground to a
Radda [10]

Answer:

false 20 n x 0.32 m = 6.4 J

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4 years ago
What is the density Ïh of hot air inside the balloon? assume that this density is uniform throughout the balloon. express the de
Deffense [45]
According to your formula, because Th>Tc, the density of hot air greater than the density of cold air.<span>Hint: You can rearrange the ideal gas law to get </span>


<span>Reference https://www.physicsforums.com/threads/density-of-hot-air.528991/</span>
8 0
3 years ago
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