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astra-53 [7]
3 years ago
5

A small rubber ball is thrown at a heavier, larger basketball that is still. The small ball bounces off the basketball. Assume t

here are no outside forces acting on the balls.
A. How does the force on the small ball compare to the force on the basketball?
B. Compare the total momentum of the two balls before and after the collision?
C. The mass of the basketball is 600 grams and its velocity before the small ball hits is 0 m/s. The mass of the small ball is 100 grams and its velocity is +5 m/s before the collision and -4 m/s afterward. What is the velocity of the basketball after the collision?
Physics
2 answers:
svp [43]3 years ago
6 0
The forces are the same for part A 
lina2011 [118]3 years ago
6 0

A 100-gram rubber ball was launched at a wall with different amounts of force. The speed of the ball was measured after it hit the wall and bounced off. The table below shows the data collected during the investigation.

Force Investigation Data

Launch Force on Ball Return Speed after Bounce

0.5 N 5 m/s

1.5 N 9 m/s

2.0 N 18 m/s

Which of the following best explains the trend shown by the data?

A 100-gram rubber ball was launched at a wall with different amounts of force. The speed of the ball was measured after it hit the wall and bounced off. The table below shows the data collected during the investigation.

Force Investigation Data

Launch Force on Ball Return Speed after Bounce

0.5 N 5 m/s

1.5 N 9 m/s

2.0 N 18 m/s

Which of the following best explains the trend shown by the data?

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Which city has already hosted the Olympic Games three times?
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London, it has hosted the 1908, 1948 and the 2012 summer olympics
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4 years ago
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A forklift raises a crate weighing 8.35 × 102 newtons to a height of 6.0 meters. What amount of work does the forklift do?
Vinil7 [7]
Answer:

<span>5010J</span>

Explanation:

Work is force times distance, or

<span>W=F⋅d</span>.

Substitute in values from the question to get

<span>W=8.35⋅<span>102</span>N⋅6m=50.1⋅<span>102</span>Nm=5010<span>J</span></span>

6 0
3 years ago
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7. A neutron at rest decays (breaks apart) into a proton and an electron. Energy is released in the decay, in the form of kineti
kondaur [170]

Answer:

The fraction of the total energy goes into kinetic energy of proton is 5.44 \times 10^{-4}

Explanation:

Given:

Mass of proton m_{p} = 1836 m_{e}

Mass of electron m_{e} = 9.1 \times 10^{-31} kg

Here neutron at rest decays into proton and electron

   n_{1} ^{0}  ⇄ P_{1} ^{1} + e_{0} ^{-1} + Q

Where Q = energy released

The Q value of this reaction is given by

    Q = (\frac{m_{p} +m _{e} }{m_{e} } ) K

Where K = kinetic energy of reaction

Here we need to find fraction of the total energy released goes into the kinetic energy of the proton

   \frac{K}{Q}  = \frac{m_{e} }{m_{p} + m_{e}  }

   \frac{K}{Q} = (\frac{m_{e} }{1836m_{e} + m_{e}  } )

   \frac{K}{Q} = \frac{1}{1837}

   \frac{K}{Q} = 5.44 \times 10^{-4}

Therefore, the fraction of the total energy goes into kinetic energy of proton is 5.44 \times 10^{-4}

6 0
3 years ago
You push a 28kg wheelbarrow forward at a constant velocity with 600 N of force. How much is friction pushing backwards?
AlladinOne [14]

F = applied force on the wheelbarrow in forward direction = 600 N

f = frictional force pushing in backward direction of wheelbarrow = ?

m = mass of the wheelbarrow = 28 kg

Since wheelbarrow moves forward at a constant velocity

a = acceleration of the wheelbarrow in forward direction = 0 m/s²

force equation for the motion of wheelbarrow in forward direction is given as

F - f = ma

inserting the above values in the formula

600 - f = (28) (0)

600 - f = 0

f = 600 N

hence the frictional force comes out to be 600 N

7 0
3 years ago
What is the difference between speed and velocity ?
oee [108]

velocity describes speed with direction.

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3 years ago
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