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san4es73 [151]
3 years ago
14

A wave has a frequency of 540 Hz and is traveling at 340 m/s. What is its wavelength?

Physics
1 answer:
EastWind [94]3 years ago
8 0

Answer:

wavelength of wave = 62.69 cm

Explanation:

Given

frequency of wave = 540 Hz = 540 s^{-1}

Speed of wave = 340 ms^{-1}

wavelength of wave = ?

We know that for all waves, the relationship between wavelength λ, frequency f and speed v is same and given by the equation:

v = fλ

Hence wavelength λ  = v/f

                                   = 340 ms^{-1} / 540 s^{-1}

                                   = 0.6296 m

                                    = 62.69 cm

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Energy Conservation With Conservative Forces: If a spring-operated gun can shoot a pellet to a maximum height of 100 m on Earth,
crimeas [40]

Answer:

h' = 603.08 m

Explanation:

First, we will calculate the initial velocity of the pellet on the surface of Earth by using third equation of motion:

2gh = Vf² - Vi²

where,

g = acceleration due to gravity on the surface of earth = - 9.8 m/s² (negative sign due to upward motion)

h = height of pellet = 100 m

Vf = final velocity of pellet = 0 m/s (since, pellet will momentarily stop at highest point)

Vi = Initial Velocity of Pellet = ?

Therefore,

(2)(-9.8 m/s²)(100 m) = (0 m/s)² - Vi²

Vi = √(1960 m²/s²)

Vi = 44.27 m/s

Now, we use this equation at the surface of moon with same initial velocity:

2g'h' = Vf² - Vi²

where,

g' = acceleration due to gravity on the surface of moon = 1.625 m/s²

h' = maximum height gained by pellet on moon = ?

Therefore,

2(1.625 m/s²)h' = (44.27 m/s)² - (0 m/s)²

h' = (1960 m²/s²)/(3.25 m/s²)

<u>h' = 603.08 m</u>

4 0
2 years ago
Calculate the rate of heat conduction through a layer of still air that is 1 mm thick, with an area of 1 m, for a temperature of
max2010maxim [7]

Answer:

The rate of heat conduction through the layer of still air is 517.4 W

Explanation:

Given:

Thickness of the still air layer (L) = 1 mm

Area of the still air = 1 m

Temperature of the still air ( T) = 20°C

Thermal conductivity of still air (K) at 20°C = 25.87mW/mK

Rate of heat conduction (Q) = ?

To determine the rate of heat conduction through the still air, we apply the formula below.

Q =\frac{KA(\delta T)}{L}

Q =\frac{25.87*1*20}{1}

Q = 517.4 W

Therefore, the rate of heat conduction through the layer of still air is 517.4 W

6 0
3 years ago
Read 2 more answers
As water across the surface of the earth it dissolves material as it travels. What property of water does this demonstrate?
iris [78.8K]

Answer:

B) Water is a solvent

Explanation:

Among many other chemicals, water can dissolve a variety of substances. The solvent properties of chemicals are far beyond it. That property makes water a universal solvent.

Water has one atom of oxygen and two atoms of hydrogen.

One side of the water molecule is positively charged and the other side is negatively charged. This property attracts other substances like salt and disintegrates into positive and negatively charged ions. This property is due to its physical and chemical nature.

3 0
2 years ago
How does an ocean wave transfer energy across the ocean?
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The energy travels in a disturbance, in an ocean that disturbance is a wave, so the wave makes energy and moves it through the water
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3 years ago
A parallel plate capacitor fully charged to voltage V is connected to the battery (the voltage on the plates remains fixed). If
Papessa [141]

Charge will decreases.

A parallel plate capacitor when it is fully charged to voltage V is given as:

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The capacitance of parallel plate capacitor with two plates of Area A separated by distance d and no dielectric material between plates is

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since from above equation it shows C is proportional to Q and also C is inversely proportional to distance d.

So, ATQ when d increases C will decrease which in result decreases charge on the capacitor.

Thus,  Charge will decrease.

Learn more about capacitance here:

     brainly.com/question/17115454

          #SPJ4

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