Answer: 18g
Explanation:
1 mle of glucose combusts to give 6moles of CO2 and 6moles of H2O
C6H12O6 + 6O2-------- 6CO2 + 6H2O at STP.
Multiplying 6 by 3 moles we have 18 g of CO2
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The molecular weight of H2O is 18g/mol.
Therefore, 27.9 g H2O / (1mol/18g) = 0.155 mol H2O
Calculating only for the latent heat, the heat required to be released for this amount of H2O to condense is:
40.7 kJ/mol (0.155 mol) = 6.3 kJ or -6.3 kJ since it is to be released
One mole of NaCl weighs 58.44 grams
Therefore 1L of one mole of NaCl contains 58.44 grams
1L of 0.2m NaCl contains 58.44x0.2 = 11.69grams
300mL of 0.2m NaCl contains 11.69x0.3 = 3.51 grams
