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marin [14]
3 years ago
5

Giving brainliest!!!!!

Mathematics
1 answer:
sweet [91]3 years ago
4 0

Answer: It’s C, “x+12=30; x=18 students”

Step-by-step explanation:

If Mr. Wilson has 12 more students than Mr. Star, whatever Mr. Star has (x) plus 12, should equal 30. That would make x, or the amount of students Mr. Star has, 18. This answer is included in option C.

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Find the total for items costing $149.99 with a sales tax of 5.75%
jek_recluse [69]
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5 0
3 years ago
Help please
natta225 [31]
Using V = ⅓[base area×height]
V= ⅓[ (5.5÷4)² × 2.6]
v= ⅓[ 4.92]
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8 0
3 years ago
Does the point(1, 8)satisfy the inequality y ≥ 6x + 2 ?
nalin [4]

Answer: Yes

Step-by-step explanation:

1. Substitute 1 for x

2. 6 times 1 is 6 plus 2 is 8

3.8 is equal to or greater than 8

4 0
3 years ago
I got an answer, but I only got one mark help
kaheart [24]

Answer:

The answer 323.4 is pound.

Step-by-step explanation:

First 25% and 8% together which is 33%.Then find out 33% of 980.33/100×980=323.4 pound.

So he saved 323.4 pound.

8 0
2 years ago
Read 2 more answers
If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid
Artist 52 [7]
Check the picture below.  Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm².  Also, recall, the base is a square, thus, length = width = x.

\bf \textit{volume of a rectangular prism}\\\\&#10;V=lwh\quad &#10;\begin{cases}&#10;l = length\\&#10;w=width\\&#10;h=height\\&#10;-----\\&#10;w=l=x&#10;\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\&#10;-------------------------------\\\\&#10;\textit{surface area}\\\\&#10;S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h&#10;\\\\\\&#10;\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\&#10;-------------------------------\\\\&#10;V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3

so.. that'd be the V(x) for such box, now, where is the maximum point at?

\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2&#10;\\\\\\&#10;\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100&#10;\\\\\\&#10;x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it.  Check the second picture below.

so, the volume will then be at   \bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3

6 0
3 years ago
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