1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Olegator [25]
2 years ago
11

Harrison and Sherrie are making decisions about their bank accounts. Harrison wants to deposit $200 as a principle amount, with

an interest of 2% compounded quarterly. Sherrie wants to deposit $200 as the principle amount, with an interest of 4% compounded monthly. Explain which method results in more money after 2 years. Show all work. (10 points)
Mathematics
1 answer:
DedPeter [7]2 years ago
5 0

Answer:

Harrison earns: $208.14

Sherrie earns: $216.57

Step-by-step explanation:

Sherrie earns more money than Harrison in 2 years.

You might be interested in
Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-
djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

A(x_{1}, y_{1}})=(-20, 25)

B(x_{2}, y_{2}})=(30, 25)

C(x_{3}, y_{3}})=(30, -10)

D(x_{4}, y_{4}})=(-20, -10)

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}

AB=\sqrt{(30+20)^{2}}

AB=\sqrt{(50)^{2}

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}

BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}

BC=\sqrt{(-35)^{2}}

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}

DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}

DC=\sqrt{(30+20)^{2}}

DC=\sqrt{(50)^{2}}

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}

AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}

AD=\sqrt{(-20+20)^{2}+(-35)^{2}}

AD=\sqrt{(-35)^{2}}

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0
3 years ago
What is the answer to the equation -(-(-(-2)))
marysya [2.9K]

Answer:

2

Step-by-step explanation:

Since there are four negative signs, we have -1 multiplying each other 4 times,  multiplying by positive 2. This is then 1 * 2, which is 2.

7 0
3 years ago
Read 2 more answers
Which of the following is a multiple of 4?
bagirrra123 [75]
The answer is A. if you divide 620 by four you would get 155 and the rest would have a decimal
4 0
3 years ago
Read 2 more answers
Determine whether or not the vector field is conservative. if it is, find a function f such that f = ∇f. if the vector field is
amm1812
\dfrac{\partial f}{\partial x}=3y^2z^3\implies f(x,y,z)=3xy^2z^3+g(y,z)

\dfrac{\partial f}{\partial y}=6xyz^3+\dfrac{\partial g}{\partial y}=6xyz^3
\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)

\dfrac{\partial f}{\partial z}=9xy^2z^2+\dfrac{\mathrm dh}{\mathrm dz}=9xy^2z^2
\implies\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=C

\implies f(x,y,z)=3xy^2z^3+C

The potential function exists, so \mathbf f is indeed conservative.
7 0
3 years ago
The length of a rectangle is 3131 inches greatergreater than twice the width. if the diagonal is 2 inches more than the​ length,
Gala2k [10]

We have a rectangle with a diagonal included. That means we have to use Pythagorean's Theorem to find the missing dimensions. We start with the width as w. The length is 31 more than twice the width, so the length is 2w+31. The hypotenuse (diagonal) is 2 more than the length, so the diagonal measures 2w+33. In a right triangle, the hypotenuse is always the longest side, so we set up Pythagorean's Theorem using the bolded values as such: (2w+33)^2=w^2+(2w+31)^2. Distributing by multiplying we simplify to 4w^2+132w+1089=w^2+4w^2+124w+961. We need to solve for w. Once we do that we can use that value to find the length. What's nice is that the 4w^2 terms cancel each other out. So when we combine like terms and get them all on one side of the equals sign to factor we have w^2-8w-128=0. The 2 numbers that add up to -8 and multiply to -128 are 16 and -8. So the width is either 16 inches or the width is -8 inches. The 2 things in math that will never EVER be negative are time and distance/length. So -8 is out. The width is 16 inches. That means that the length is 2(16)+31, which is 63 inches. There you go!

8 0
3 years ago
Other questions:
  • Can you help me with these two?
    14·2 answers
  • A moving company charges $40 plus $0.10 per mile to rent a moving van. Another company charges $10 plus $0.25 per mile to rent t
    11·1 answer
  • By what percent will the product of two numbers decrease if one of them is increased by 30% and the other is decreased by 30%?
    6·2 answers
  • Shannon evaluated the expression 9-6+12÷(3×2) and got the answer 14. Is she correct?
    12·2 answers
  • HELP THANKS SO MUCH BRAIN FOR CORRECT
    8·1 answer
  • What is the value of f(n + 3)?
    9·1 answer
  • A hairdresser receives a discount on each comb purchased. The original price of each comb is x dollars. The hairdresser purchase
    10·1 answer
  • A mass oscillating up and down on the bottom of a spring (assuming perfect elasticity and no friction or air resistance) can be
    9·1 answer
  • Write an equation in point-slope form that has a y-intercept at (0, 12) and also contains the point (1,2)
    8·1 answer
  • Help!
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!