In a survey, one-fifth youths like cell phone only and 16 did not like cell phone at all. Also 60%

Mathematics

1 answer:

Pepsi [2]3 years ago

6 0

Answer: Let, n(U) be=x only (p)=x/5 only(ca)=16 n(pnc)=?n(c)=60%ofx=0.6x

then,

Only (c)=n(c)-n(cnp)

16=0.6x-n(cnp)

n(cnp)=0.6x-16

again,

n(U)=only(p)+only (c)+n(cnp)+n(pUc)of complement

x=x/5+16+0.6x-16+8

5x=x+3x+40

x=40

n(cnp)=0.6x-16=0.6×40-16=8

Step-by-step explanation:

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Answer:

0.62% probability that randomly chosen salary exceeds $40,000

Step-by-step explanation:

Problems of normally distributed distributions are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

$\mu = 30000, \sigma = 4000$