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3 years ago

the grams of carbohydrate in one apple if the apple has no fat and no protein and provides 72 kcal of energy

1 answer:

5 0

<span>Carbohydrates have 4 kcal per gram of carbohydrates. (Protein is also 4 kcal/gram, while fat is 9 kcal/gram). Take the total kcal and divide by 4 kcal/gram: 72 kcal/(4 kcal/gram) = 18 grams carbohydrates.</span>

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Electron configuration for Lithium.

Ira Lisetskai [31]

The answer to problem is [He] 2s1. Hope it helps

4 0

3 years ago

Read 2 more answers

Collected data consists of:

san4es73 [151]

The number of moles of the magnesium (mg) is 0.00067 mol.

The number of moles of hydrogen gas is 0.0008 mol.

The volume of 1 more hydrogen gas (mL) at STP is 22.4 L.

<h3>Number of moles of the magnesium (mg)</h3>

The number of moles of the magnesium (mg) is calculated as follows;

number of moles = reacting mass / molar mass

molar mass of magnesium (mg) = 24 g/mol

number of moles = 0.016 g / 24 g/mol = 0.00067 mol.

<h3>Number of moles of hydrogen gas</h3>

PV = nRT

n = PV/RT

Apply Boyle's law to determine the change in volume.

P1V1 = P2V2

V2 = (P1V1)/P2

V2 = (101.39 x 146)/(116.54)

V2 = 127.02 mL

Now determine the number of moles using the following value of ideal constant.

R = 8.314 LkPa/mol.K

n = (15.15 kPa x 0.127 L)/(8.314 x 290.95)

n = 0.0008

<h3>Volume of 1 mole of hydrogen gas at STP</h3>

V = nRT/P

V = (1 x 8.314 x 273) / (101.325)

V = 22.4 L

Learn more about number of moles here: brainly.com/question/13314627

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7 0

1 year ago

Question 1<br>Write the next three numbers in the sequence<br>2, 10, 50, 250,-<br>

Bess [88]

1250, 6250, and 31250

8 0

3 years ago

A sample of oxygen gas is compressed from 30.6 L to 1.8 L at constant temperature pressure of 1.8 atm. Calculate the amount of e

ad-work [718]

Answer:

the change in the internal energy of the system is 3,752.67 J

Explanation:

Given;

initial volume of the gas, V₁ = 30.6 L

final volume of the gas, V₂ = 1.8 L

constant pressure of the gas, P = 1.8 atm

Energy released by the system, Q = 1.5 kJ = 1,500 J

Apply pressure-volume work equation, to determine the work done on the gas;

w = -PΔV

w = -P(V₂ - V₁)

w = - 1.8 atm(1.8 L - 30.6 L)

w = 51.84 L.atm

w = 51.84 L.atm x 101.325 J/L.atm

w = 5,252.67 J

The change in the internal energy of the system is calculated as;

ΔU = Q + w

Since the heat is given out, Q = - 1,500 J

ΔU = -1,500 J + 5,252.67 J

ΔU = 3,752.67 J

Therefore, the change in the internal energy of the system is 3,752.67 J

3 0

3 years ago

Construct a simulated 1H NMR spectrum, including proton integrations, for CH3OC(CH2OCH3)3 (see Hint). Drag the appropriate split

CaHeK987 [17]

Answer:

The drawing of the structure is found in diagram 1 of the attached figure.

Explanation:

Diagram 1 shows that three different types of protons are found in the structure. The nine hydrogen atoms have a similar behavior, the six hydrogen atoms also have a similar behavior and finally, the three hydrogen atoms adjacent to oxygen have a similar behavior. The number of peaks are as follows:

9H = singlet peak = between 3 and 4 ppm

6H = singlet peak = 4 ppm

3H = singlet peak = 3 ppm.

The 9 protons are around 3.5 ppm and the 6 hydrogen atoms show a peak at 4 ppm, and finally, the 3 protons have a peak around 3 ppm. Therefore, the corresponding drawing can be seen in diagram 2.

4 0

3 years ago