Answer:
- <u>21.4 ml (second choice)</u>
Explanation:
<u>1) Data:</u>
a) C₁ = 60.0% (initial solution)
b) V₁ = 30.0 ml (initial solution)
c) C₂ = 0% (pure water)
d) V₂ = ? (pure water)
e) C₃ = 35.0% (final concentration)
<u>2) Formula:</u>
- C₁V₁ + C₂V₂ = C₃V₃
- V₁ + V₂ = V₃ (assuming volume addtivity)
<u>3) Solution:</u>
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a) Substitute values in the first formula:
- 60.0% × 30 ml + 0 = 35% (30 ml + V₂)
b) Solve the equation (units are supressed just to manipulate the terms)
- V₂ = 7.5 / 0.35 = 21.4 ml ← answer
Answer:
H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)
Explanation:
H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq) + SO²⁻₄(aq) + H₂O(l)
A careful observation of the equation above, shows that the equation is already balanced.
To obtain the net ionic equation, we simply cancel Mg²⁺ from both side of the equation as shown below:
H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)
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