Answer:
The correct option is (c)
Answer:
Determine how many moles of CO2 are required to produce 11.0 mol of glucose,
i need points thanks for CO2moles
Answer:
28.497 cm3
Explanation:
Formula
D=m/v
Given data:
density = 19.3g/cm3
mass = 550 g
Now we will put the values in formula:
V=m/d
V=550 g/ 19.3 g/cm3 = 28.497 cm3
So the volume of gold is 28.497 cm3.