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DerKrebs [107]
3 years ago
12

Help!!!!! please there is no question just fill in the question marks

Chemistry
2 answers:
anzhelika [568]3 years ago
6 0
2 grams :) djdjdjdjsjwjdkndncp
Vaselesa [24]3 years ago
3 0

Answer:

32 grams

Explanation:

Ignore the other answer. Two oxygen atoms have a mass of 32 grams. You can also arrive at this answer by subtracting the given values (i.e. 36 - 4 = 32).

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3 years ago
Based on these data, what is the value of the formation constant, Kf, of [Cu(NH3)4]2+? [Cu 2+ ]=6.47x10 -15 kf=
bonufazy [111]
I dont even know to be honest
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3 years ago
Yucca moths lay eggs in yucca flowers. When the eggs hatch, the larvae eat yucca seeds. The moths help pollinate the flowers. Wh
liberstina [14]
A. Mutualism. This is because both the larvae and the flower are benefited. The larvae is fed, and the flower is pollinated.

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8 0
3 years ago
When 3.93 grams of lactic acid, CHoOs(s), are burned in a bomb
aliya0001 [1]

The heat released in the combustion of lactic acid is absorbed by the

calorimeter and in the decomposition of the lactic acid.

ΔH°f of lactic acid is approximately <u>-716.2 kJ</u>

Reasons:

Known parameters are;

Mass of the lactic acid = 3.93 grams

Heat  capacity of the bomb calorimeter = 10.80 kJ·K⁻¹

Change in temperature of the calorimeter, ΔT = 5.34 K

ΔHrxn = ΔErxn

ΔH°f of H₂O(l) = -285.8 kJ·mol⁻¹

ΔH°f of CO₂(g) = -393.5 kJ·mol⁻¹

The chemical equation for the reaction is presented as follows;

  • C₃H₆O₃ + 2O₂ → 3CO₂ + 3H₂O

The heat of the reaction = 10.80 kJ·K⁻¹ × 5.34 K = 57.672 kJ

Molar mass of C₃H₆O₃ = 90.07 g/mol

Number of moles of C₃H₆O₃ = \dfrac{3.93 \, g}{90.07 \, g/mol} = 0.043633 moles

Number of moles of CO₂ produced = 3 × 0.043633 moles = 0.130899 moles

Heat produced = 0.130899 mole × -285.8 kJ·mol⁻¹ = -37.4109342 kJ

Moles of H₂O produced = 0.130899 moles

Heat produced = 0.130899 mole × -393.5 ≈ -51.51 kJ

Therefore, we have;

Heat absorbed by the lactic acid = ΔH°f of H₂O + ΔH°f of CO₂ + Heat absorbed by the calorimeter

Which gives;

Heat absorbed by lactic acid  = -37.4109342 kJ - 51.51 kJ + 57.672 kJ ≈ -31.249 kJ

The heat absorbed by the lactic acid ≈ -31.249 kJ

  • \Delta H^{\circ}f \ of \ C_3H_6O_3 = \dfrac{-31.249}{0.043633} \approx  -716.2

ΔH°f of C₃H₆O₃ ≈ -716.2 kJ

Heat of formation of lactic acid ≈ <u>-716.2 kJ</u>.

Learn more here:

brainly.com/question/13185938

5 0
2 years ago
A block of aluminum with a mass of 140 g is cooled from 98.4°C to 62.2°C with a release of 4817 J of heat. From these data, calc
disa [49]

Answer:

specific heat = 0.951 j/g·°C

Explanation:

Heat flow equation  => q = m·c·ΔT

q = heat flow = 4817 joules

m = mass in grams = 140 grams Aluminum

c = specific heat = ?

ΔT = Temperature Change in °C = 98.4°C - 62.2°C = 36.2°C

q = m·c·ΔT => c = q/m·ΔT = 4817j/(140g)(36.2°C) = 0.951 j/g·°C

6 0
3 years ago
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