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erma4kov [3.2K]
3 years ago
13

An empty parallel plate capacitor is connected between the terminals of a 8.85-V battery and charges up. The capacitor is then d

isconnected from the battery, and the spacing between the capacitor plates is doubled. As a result of this change, what is the new voltage between the plates of the capacitor
Physics
1 answer:
kipiarov [429]3 years ago
3 0

Answer:

The new voltage is 17.7 V.  

Explanation:

Voltage, V = 8.85 V

The spacing is doubled.

When it is disconnected, the charge remains same,

q = C V ..... (1)

where, C is the capacitance, V is the voltage.  

The capacitance is inversely proportional to the distance between the two plates.

So, when the spacing is doubled, the capacitance is halved.

Let the new voltage is V'.

C V = C' V'

C x 8.85 = C/2 x V'

V' = 17.7 V  

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Answer:

Planning and performing an experiment to answer the question.

Explanation:

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Frosty the Snowman accelerates from 16 m/s to 26 m/s in 2 s. What is his acceleration?
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Answer:

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Explanation:

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3 years ago
A laser beam of wavelength 600 nm is incident on two slits that are separated by 0.02 mm. What is the separation between adjacen
Liula [17]

Answer:

option D

Explanation:

given,

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d \times \dfrac{y_m}{L}=m\lambda

for (m+1)th order maxima

d \times \dfrac{y_{m+1}}{L}=(m+1)\lambda

now,

y_m=\dfrac{mL\lambda}{d}      and

y_{m+1}=\dfrac{(m+1)L\lambda}{d}

hence,

\Delta y = y_{m+1} - y_m

\Delta y =\dfrac{L\lambda}{d}

\Delta y =\dfrac{5 \times 600 \times 10^{-9}}{0.02 \times 10^{-3}}

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4 0
4 years ago
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Answer:

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With these values:

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I'm gonna have to guess B) Automation sorry if I get it incorrect

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Read 2 more answers
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