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3 years ago

6. A car travels a distance of 10 miles in 2 minutes towards 695 north east. 3 points

Physics

1 answer:

damaskus [11]3 years ago

5 0

Answer:

C. 5 miles/ minute north east

Explanation:

magnitude = 10 mi / 2 min = 5 mi/min

Velocity is a vector

A vector always has both a magnitude and direction

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If two connected points objects pass through the same set of three points, the shapes created by each will be identical, regardl

NeX [460]

Answer:

This is false

Explanation:

This is why the answer to this question is false. If these types of objects (2 points connected) should pass through same sets of 3 points, irrespective of the order that each object was plotted, we will not get identical shapes created.

The shape that is going to be created will be dependent on the pattern/order that was involved in the plotting. If it was identical, then we will have identical shapes. But if the order during plotting is different then we will have different shapes created.

Thank you!

5 0

3 years ago

20 points!

MariettaO [177]

Do they give answer choices? or is it free write? i’ll help if you tell me!!

8 0

3 years ago

How much equal charge should be placed on the earth and the moon so that the electrical repulsion balances the gravitational for

kumpel [21]

As we know that electrostatic force between two charges is given as

$F = \frac{kq_1q_2}{r^2}$

here we know that electrostatic repulsion force is balanced by the gravitational force between them

so here force of attraction due to gravitation is given as

$F_g = 1.98 \times 10^{20} N$

here we can assume that both will have equal charge of magnitude "q"

now we have

$1.98 \times 10^{20} = \frac{kq^2}{r^2}$

$1.98 \times 10^{20} = \frac{(9\times 10^9)(q^2)}{(3.84 \times 10^8)^2}$

$1.98 \times 10^{20} = (6.10 \times 10^{-8}) q^2$

now we have

$q = 5.7 \times 10^{13} C$

6 0

3 years ago

Calculate the current passing through a conductor of resistance 4ohms. If a potential difference of 15V its ends______

statuscvo [17]

Explanation:

current = velocity/resistance

I = V/R

15/4

current = 3.75A

hope this helps...

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3 years ago

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tangare [24]

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3 years ago