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AnnyKZ [126]
3 years ago
12

When a rocket is launched into the sky, what force must it overcome?

Physics
2 answers:
Kobotan [32]3 years ago
4 0

Answer:

B) gravity

Explanation:

For a rocket to launch, it must overcome the force of gravity acting on it. For this, it produces an upward force (thrust) that "fights" against the force that is pulling it downward (gravity).

To produce the buoyant force, the rocket engines produce combustion gases, usually using liquid hydrogen as fuel and liquid oxygen as the oxidizer, these gases are expelled by the rocket nozzles, pushing against the upper wall of the nozzles. The relationship between the forces can be summed up by Newton's third law, in which every action causes a reaction of equal force and direction and opposite direction, the gases are expelled with such a force that it exceeds the force of the rocket, propelling it upwards .

Brut [27]3 years ago
3 0
The answer is b 
 hope this helped
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Consider a hydrogen atom in the n = 1 state. The atom is placed in a uniform B field of magnitude 2.5 T. Calculate the energy di
dlinn [17]

Answer:

E=29\times 10^{-5}eV

Explanation:

For n-=1 state hydrogen energy level is split into three componets in the presence of external magnetic field. The energies are,

E^{+}=E+\mu B,

E^{-}=E-\mu B,

E^{0}=E

Here, E is the energy in the absence of electric field.

And

E^{+} and E^{-} are the highest and the lowest energies.

The difference of these energies

\Delta E=2\mu B

\mu=9.3\times 10^{-24}J/T is known as Bohr's magneton.

B=2.5 T,

Therefore,

\Delta E=2(9.3\times 10^{-24}J/T)\times 2.5 T\\\Delta E=46.5\times 10^{-24}J

Now,

Delta E=46.5\times 10^{-24}J(\frac{1eV}{1.6\times 10^{-9}J } )\\Delta E=29.05\times 10^{-5}eV\\Delta E\simeq29\times 10^{-5}eV

Therefore, the energy difference between highest and lowest energy levels in presence of magnetic field is E=29\times 10^{-5}eV

6 0
3 years ago
2/25/20 or 2/28/20 Dispatch #53
mixer [17]

Answer:

Power = 21[W]

Explanation:

Initial data:

F = 35[N]

d = 18[m]

In order to solve this problem we must remember the definition of work, which tells us that it is equal to the product of a force for a distance.

Therefore:

Work = W = F*d = 35*18 = 630 [J]

And power is defined as the amount of work performed in a time interval.

Power = Work / time

Time = t = 30[s]

Power = 630/30

Power = 21 [W]

3 0
3 years ago
uniform electric field exists between two parallel plates separated by 2.0 cm. The intensity of the field is 15 kN/C. What is th
adoni [48]

Answer:

potential difference V= 300 volts

Explanation:

Given:

d= 2.0 cm = 0.02m

E = 15 kN/C = 15 × 10³ N/C

For a uniform field between two plates, the Electric Filed Intensity (E) is proportional to the potential difference (V) and inversely  proportional to distance between the plates.

E= V/d

⇒ V= E×d = 15 × 10³ N/C × 0.02 m = 300 volts  (∴1 Nm/C = 1 J/C= 1 volts)

7 0
3 years ago
PLz I Need Help PLZZZ ASAP
AURORKA [14]

#1

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#2

As we are changing the amplitude in the simulation there is no change in the speed frequency and wavelength.

So amplitude is independent of all these parameter

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#3

In our daily life we deal with two waves

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2 light waves

3 0
3 years ago
A force of 1 N will cause a mass of 1 kg to have an acceleration of 1 m/s2. Therefore, a force of 7 N applied to a mass of 7 kg
Lana71 [14]

1 m/s^2

Using F=ma,

7=7a

a=1

3 0
3 years ago
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