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iris [78.8K]
3 years ago
5

A wave with a frequency of 196 Hz

Physics
1 answer:
Marysya12 [62]3 years ago
3 0

Answer:

1372

Explanation:

use the  speed formula

Speed=wavelength x frequency

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Determine the farthest away a car can be at night so that your eyes can resolve the two headlights. Assume that the the diameter
Zigmanuir [339]

Answer:

The farthest distance is L_{max}=11.48 km

Explanation:

The angular resolution is mathematically represented as

              \theta = \frac{Z}{L} = \frac{1.22 \lambda}{d}

Where Z is the distance between the car head lamp with a value Z = 1.4 m

L is the distance between the eye and the car

\lambda is the wavelength  with a value 500 nm = = 500 *10^{-9}m

d is the diameter of the eye with a value  d = 0.50 cm = = \frac{0.50}{100} = 0.005m

   The maximum distance L_{max} is given as

              L_{max} = \frac{(1.4) *0.005}{1.22 * (500 *10^{-9})}

                       = 11.48*10^{3}m

                        =11.48 km

             

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4 years ago
[OU.04]What type of galaxy is described as having a circular shape with most of the objects concentrated around its center? spir
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Answer:

spiral

Explanation:

A galaxy may be defined as the huge collection of celestial bodies like the stars, planets, dark matters, dust and gases and the solar systems. It is derived from the Greek work, 'Galaxias' , which means "milky". There are many types of galaxies. They are : Spiral galaxy, Elliptical galaxy, Irregular galaxy and Barred spiral galaxy.

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3 years ago
A ball is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the wa
vovangra [49]

Answer:

a) 48.5 ft/s

b) 36.5 ft

c) -80.3 ft/s

Explanation:

a)

The equation of motion of the ball is :

y(t) = -16.1 ft/s^2 * t^2 + Vo*t

Where Vo is the initial velocity

If y(5s) = - 160 ft:

-160 ft = -16.1 ft/s^2 * (5 s)^2 + Vo*(5s)

Solving for Vo

Vo  = (16.1*25- 160) ft / 5s = 48.5 ft/s

b)

To answer this question we must first know when the velocity became zero, at this time is when the ball was at its highest point.

v(t) = -32.2 ft/s^2 * t + Vo

t = Vo/32.2ft/s^2 = 1.5 s

And now, the highest point which the ball reached is given by:

y(1.5s) = -16.1 ft/s^2 * (1.5)^2 + Vo*(1.5s)

y(1.5s) = 36.52 ft

c)

We now need the time at which y(t') = -64 ft

-64 = -16.1*t'^2 + 48.5*t'

By means of the quadratic formula, we find that

t' = 4.00498 s ≈ 4 s

And the velocity at t = 4s is:

v(4s) = -32.2 ft/s^2 * 4s +48.5 ft/s = -80.3 ft/s

3 0
4 years ago
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