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3 years ago

Any 4 differences between latitudes and longitudes..

Physics

1 answer:

MrMuchimi3 years ago

6 0

Answer:

latitude implies the geographic coordinates that determine the distance of a point, north- South of the equator. longitude alludes to the geographic coordinates, which indentifies the distance of a point, east-west of the prime meridian.

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A circular coil has a 18.0 cm radius and consists of 25.0 closely wound turns of wire. An externally produced magnetic field of

djverab [1.8K]

Answer:

The magnetic flux links to its turns = $7.6 \times10^{-3}$ Wb.

Explanation:

Given :

Radius of circular coil = $18 \times 10^{-2}$ m

Number of turns = 25

Magnetic field = $3 \times10^{-3}$ T

Magnetic flux (Φ) is a measure of the magnetic field lines passes through a given area. The unit of magnetic flux is weber (Wb).

We know that,

⇒ Φ = $BA$

Where $B =$ ext. magnetic field, $A =$ area of loop or coil.

But here given in question, we have turns of wire so our above eq. modified as follows.

⇒ Φ = $NBA$

Where $N =$ no. of turns.

∴ Φ = $25 \times 3 \times 10^{-3} \pi (18 \times10^{-2} )^{2}$

Φ = $7.6 \times 10^{-3} Wb$

Thus, the magnetic flux links to its turns = $7.6 \times 10^{-3} Wb$

3 0

4 years ago

10%) Problem 7: Water flows through a water hose at a rate of Q1 = 620 cm3/s, the diameter of the hose is d1 = 1.99 cm. A nozzle

Semenov [28]

Answer:

a) $A_1 = \frac{\pi d_1^2}{4}$

Explanation:

a) the cross-sectional area of the hose would be the square of radius times pi. And since the sectional radius is half of its diameter d. We can express the cross-sectional area A1 in term of diameter d1

$A_1 = \pi r_1^2 = \pi (d_1/2)^2 = \frac{\pi d_1^2}{4}$

6 0

3 years ago

What would the answer be ?

Marianna [84]

The second one since you’re changing the soil up by adding different fertilisers. This will be you’re independent variable. And you’re dependent variable is your result = the plant height .
Hope this helps :)

4 0

3 years ago

A manometer that is filled with water (rho=1000 kg/m3) is connected to a wind tunnel to measure the pressure inside the test sec

Anna [14]

To develop this problem it is necessary to apply the concepts performed to the absolute pressure based on the reference pressure (atmospheric) and the pressure that is generated due to the height of the column of the measured liquid.

In mathematical terms the previous concept can be expressed as

$P_{abs} = P_{atm} -\rho gh$