Question

A 50 g tennis ball travels at a velocity of 15 m/s, hits a basketball with a mass of 600 g that is stationary on a frictionless surface and then rebounds back in the opposite direction with a velocity of -6 m/s . How fast will the basketball be moving after the collision? m/s

Answer 1

Answer:

1.75 m/s

Explanation:

Momentum is conserved.

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

(50 g) (15 m/s) + (600 g) (0 m/s) = (50 g) (-6 m/s) + (600 g) v

v = 1.75 m/s