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3 years ago

Select the correct answer from each drop-down menu.

Engineering

1 answer:

weeeeeb [17]3 years ago

8 0

Answer:

In engineering, the most basic or primary unit of measurement used for drafting is the <u>millimeter</u> and the <u>meter</u>, followed by the <u>kilometer</u>

Explanation:

Based on the the SI system of units, in engineering, the most basic or primary unit of measurement used for drafting is the millimeter and the meter, followed by the kilometer

The millimeter is used in mechanical and an architectural drawing, the meter is used architectural drawing, while civil dimensioning make use of the kilometer

In the US it is customary to use the inches and a fraction of an inch is used as a scale in scale drawings

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Neon is compressed from 100 kPa and 20◦C to 500 kPa in an isothermal compressor. Determine the change in the specific volume and

PIT_PIT [208]

Answer:

The specific volume is reduced in 80 per cent due to isothermal compression.

Specific enthalpy remains constant.

Explanation:

Let suppose that neon behaves ideally, the equation of state for ideal gases is:

$P\cdot V = n\cdot R_{u}\cdot T$

Where:

$P$ - Pressure, measured in kilopascals.

$V$ - Volume, measured in cubic meters.

$n$ - Molar quantity, measured in kilomoles,

$T$ - Temperature, measured in kelvins.

$R_{u}$ - Ideal gas constant, measured in $\frac{kPa\cdot m^{3}}{kmol\cdot K}$ .

On the other hand, the molar quantity ( $n$ ) and specific volume ( $\nu$ ), measured in cubic meter per kilogram, are defined as:

$n = \frac{m}{M}$ and $\nu = \frac{V}{m}$

Where:

$m$ - Mass of neon, measured in kilograms.

$M$ - Molar mass of neon, measured in kilograms per kilomoles.

After replacing in the equation of state, the resulting expression is therefore simplified in term of specific volume:

$P\cdot V = \frac{m}{M}\cdot R_{u}\cdot T$

$P\cdot \nu = \frac{R_{u}\cdot T}{M}$

Since the neon is compressed isothermally, the following relation is constructed herein:

$P_{1}\cdot \nu_{1} = P_{2}\cdot \nu_{2}$

Where:

$P_{1}$ , $P_{2}$ - Initial and final pressure, measured in kilopascals.

$\nu_{1}$ , $\nu_{2}$ - Initial and final specific volume, measured in cubic meters per kilogram.

The change in specific volume is given by the following expression:

$\frac{\nu_{2}}{\nu_{1}} = \frac{P_{1}}{P_{2}}$

Given that $P_{1} = 100\,kPa$ and $P_{2} = 500\,kPa$ , the change in specific volume is:

$\frac{\nu_{2}}{\nu_{1}} = \frac{100\,kPa}{500\,kPa}$

$\frac{\nu_{2}}{\nu_{1}} = \frac{1}{5}$

The specific volume is reduced in 80 per cent due to isothermal compression.

Under the ideal gas supposition, specific enthalpy is only function of temperature, as neon experiments an isothermal process, temperature remains constant and, hence, there is no change in specific enthalpy.

Specific enthalpy remains constant.

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3 years ago

Consider the 'scope trace showing the input signal to an rc filter (the one having the larger amplitude) and the output of the f

yulyashka [42]

The corner frequency of this filter in hz is Directly switched the documents to one-of-a-kind Cloud Multi-Regional Storage bucket places in US, EU, and Asia the usage of APIs over HTTP(S).

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2 years ago

What are some of the main causes of accidents?

Ainat [17]

Answer

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Explanation:

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4 years ago

In poor weather, you should __ your following distance

Ratling [72]

Answer:

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4 years ago

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When the grounded conductor is to be spliced in a 12-inch by 12-inch junction box, there shall be at least ? of free conductor l

slamgirl [31]

There should be a 6" free conductor left for splicing

Why there should be 6" splicing?

You must leave the junction box with at least six inches of free conductor wiring when running electrical cables from the box to the box for connecting needs.

Actually, 6-8 inches can be left when running the electric cables, additionally even if the grounded conductor is to be spliced in a 12-inch by 12-inch.

Conductor splicing: A splice, which can be finished using either the crimping or soldering method, is the joining of two or more conductors in a way that produces a permanent electrical termination and mechanical link.

Hence we can conclude that 6 inches is fine for the conductor splicing

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1 year ago