The formula is
A=p (1+r)^t
A future value 572.6
P present value 560
T time 6/12 =1/2=0.5
R interest rate?
We need to solve for r
R=(A/p)^(1/t)-1
R=(572.6÷560)^(1÷0.5)−1
R=0.0455×100
R=4.55%
Answer:
The velocity of the car after the collision is -5.36 m/s
Step-by-step explanation:
An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.
let the following:
m₁ = mass of the car = 1400 kg
m₂ = mass of the truck = 3200 kg
u₁ = velocity of the car before collision = 13.7 m/s
u₂ = velocity of the truck before collision = 0 m/s
v₁ = velocity of the car after collision
v₂ = velocity of the truck after collision
v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)
= [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)
= - 5.36 m/s
So, <u>the velocity of the car after the collision is -5.36 m/s</u>
You will need to find a common multiple of the two. For example:
2: 2, 4, 6
3: 3, 6
The common multple here is 6, so the answer is 6.
Thanks,
Whiiz
Answer if D hope it helps!
Answer:
x > 29
Step-by-step explanation:
-x < -29
~Divide -1 to both sides
x > 29
Best of Luck!