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3 years ago

What is the perimeter of this figure?

Mathematics

1 answer:

murzikaleks [220]3 years ago

7 0

Answer:

6+2+3+3+3+5=22 is a correct answer

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At Ole's Waffle Shop there are 81 dirty coffee mugs and 9 clean coffee mugs. What percentage of the coffee mugs at the waffle sh

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90 percent of the mugs are dirty

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2 years ago

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3 years ago

A plot of grass behind a building is shown.

KATRIN_1 [288]

Answer:

62m

Step-by-step explanation:

16+16+8+12+10

=62m

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3 years ago

Read 2 more answers

Isandro and Yvette each have a calculator. Yvette starts at 100 and subtracts 7 each time. Isandro starts at 0 and adds 3 each t

Talja [164]

Answer: 30

Step-by-step explanation:

Yvette- 100-7

Isandro- 0+3

1.) I'm going to speed up the process and multiply by 5.

Yvette: 100-7

7 × 5 = 35

100-35= 65

65-35= 30

Isandro: 0+3

3 × 5 = 15

0+15= 15

15+15= 30

2.) If they keep going on this pattern they will have the same number on the 10 round.

7 0

2 years ago

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago